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If a motorist had driven 1 hour longer on a certain day and

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If a motorist had driven 1 hour longer on a certain day and [#permalink] New post 25 Aug 2004, 08:08
If a motorist had driven 1 hour longer on a certain day and at an average of 5 miles per hour faster, he would have covered 70 miles more than he actually did.How many more miles would have he then covered if he had driven2 hours longer and at an average rate of 10 miles per hour faster on that day
a)100
b)120
c)140
d)150
e)160
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 [#permalink] New post 25 Aug 2004, 08:31
D.

V*t=S

(V+5)*1 = 70
Therefore, V=65 (real speed)

(65+10)*2 = 150.
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 [#permalink] New post 25 Aug 2004, 09:47
Great q, very hard in my opinion. Feel free to plug in the answers to get it - you'll have it in no time.
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 [#permalink] New post 25 Aug 2004, 11:01
Great Dookie!! I could not comprehend the part " at an average speed of 5miles per hour faster" as V+5.


Dookie wrote:
D.

V*t=S

(V+5)*1 = 70
Therefore, V=65 (real speed)

(65+10)*2 = 150.

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Awaiting response,

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 [#permalink] New post 25 Aug 2004, 11:29
Sometimes you just "see it"..
I guess i got lucky this time, because if you solve it the same way i did, it takes less than a minute.
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 [#permalink] New post 25 Aug 2004, 17:15
Dookie wrote:
Sometimes you just "see it"..
I guess i got lucky this time, because if you solve it the same way i did, it takes less than a minute.


totally agree wiht you there...
saw the question, thought to myself 'tough one'.
as soon as I put down the equations:
(t+1)(r+5)=d+70
(t+2)(r+10)=?

it all hits home once you realize that an extra hour brings you 65 more miles
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Lost :( [#permalink] New post 25 Aug 2004, 17:44
lastochka wrote:
totally agree wiht you there...
saw the question, thought to myself 'tough one'.
as soon as I put down the equations:
(t+1)(r+5)=d+70
(t+2)(r+10)=?

it all hits home once you realize that an extra hour brings you 65 more miles


Didn't get it. How is it by looking at equations we can tell that extra hour brings 65 miles.?
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Re: Lost :( [#permalink] New post 25 Aug 2004, 17:52
stmifx wrote:
lastochka wrote:
totally agree wiht you there...
saw the question, thought to myself 'tough one'.
as soon as I put down the equations:
(t+1)(r+5)=d+70
(t+2)(r+10)=?

it all hits home once you realize that an extra hour brings you 65 more miles


Didn't get it. How is it by looking at equations we can tell that extra hour brings 65 miles.?


my mistake there,
the equations to look at are:
t*r=d and
(t+1)(r+5)=d+70
from this you see that an extra hour and an extra 5 mph brings you extra 70 miles
hence, the original speed, or r, must be 65 mph.
is this better?
Re: Lost :(   [#permalink] 25 Aug 2004, 17:52
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