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if a not equal to Zero, 1/a < a/(b^4+3) 1. a^2=b^2 2. a^2

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if a not equal to Zero, 1/a < a/(b^4+3) 1. a^2=b^2 2. a^2 [#permalink] New post 18 Jun 2011, 10:32
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A
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D
E

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if a not equal to Zero,
1/a < a/(b^4+3)

1. a^2=b^2
2. a^2 = b^4


PS: Any one who has MGMAT adv Quant book can confirm ,whether the uestion is correct or there is a typo.
I dont agree with the OA . I believe there is a typo. Its page 106
[Reveal] Spoiler: OA
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Re: Inequality - MGMAT Adv Quant [#permalink] New post 18 Jun 2011, 10:52
sudhir18n wrote:
if a not equal to Zero,
1/a < a/(b^4+3)

1. a^2=b^2
2. a^2 = b^4


PS: Any one who has MGMAT adv Quant book can confirm ,whether the uestion is correct or there is a typo.
I dont agree with the OA . I believe there is a typo. Its page 106


can't be A.

(1)
a^2=b^2 --> is true for both -1 and 1 which give different answers
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Re: Inequality - MGMAT Adv Quant [#permalink] New post 18 Jun 2011, 11:03
is 1/a < a / (b^4) + 3

(1) since a can't be 0, b also can't be 0 because a^2=b^2.......any other number works here though the only problem is the sign....-1 AND 1 can work. Hence this statement by itself is insufficient.

1/(-1) < -1 / (1)^4 + 3 --> -1 < -1/4 << YES!!
1/1 < 1/1^4+3 = 1 < 1/4 << NO!!

(2)
a^2=b^4 runs into the same problem as (1). since both exponents are even, they hide the sign of their base.

Together: Doesent really make a difference. Again sign of base is hidden.

Hence, IMO
[Reveal] Spoiler:
(E)


In a question like this where both statements are giving you the exact same information, the answer is usually (D) or (E)........

(A) doesent make sense to me
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Re: Inequality - MGMAT Adv Quant [#permalink] New post 18 Jun 2011, 11:18
sudhir18n wrote:
if a not equal to Zero,
1/a < a/(b^4+3)

1. a^2=b^2
2. a^2 = b^4


PS: Any one who has MGMAT adv Quant book can confirm ,whether the uestion is correct or there is a typo.
I dont agree with the OA . I believe there is a typo. Its page 106


I don't have the book but the answer should be E.

b=1
a=1 or a="-1"

Not Sufficient combined. Please intimate them.
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Re: Inequality - MGMAT Adv Quant [#permalink] New post 20 Jun 2011, 10:17
Yes, this question was discussed at length at BTG recently. The answer is definitely E; the book is wrong.
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Re: Inequality - MGMAT Adv Quant [#permalink] New post 23 Jun 2011, 03:02
a check for 1,1; 1,-1; -1,1;-1,-1. gives different results. Not sufficient,

b checking for above values and +|-4,2 also give different results.
not sufficient.

a+b the +|- 1 gives the same results as a.

E it is.
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Re: Inequality - MGMAT Adv Quant [#permalink] New post 01 Aug 2011, 04:23
I solve this question mathematically, works better for me than plugging in numbers.

I will share if anyone wants. thanks.
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Re: Inequality - MGMAT Adv Quant [#permalink] New post 01 Aug 2011, 07:00
1. Not Sufficient

a = +- b

b =1 => a = +- 1

a = 1 , LHS > RHS
a= -1, LHS < RHS

2. Not sufficient

a = +- b^2

lets say b=1 => a = +- 1

same as 1.

together

b can be 0 ,-1 ,1

when b =1 , same situation as 1 & 2.

Not sufficient.

Answer is E.
Re: Inequality - MGMAT Adv Quant   [#permalink] 01 Aug 2011, 07:00
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