Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

If a number is a multiple of 6, then it must also be a [#permalink]
09 Apr 2005, 19:44

00:00

A

B

C

D

E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct
0% (00:00) wrong based on 0 sessions

If a number is a multiple of 6, then it must also be a multiple of 3 and it must be an even number. I have a number X which is a multiple of 3. I may assume that:
A. It must be an even number.
B. It may be an even number but doesn't have to be.
C. It cannot be an even number.
D. It cannot be a multiple of 6.
E. It can be a multiple of 6 or an even number, but not both.

I dont have any OA. just wanted to confirm my answer..

A. It must be an even number - consider 9 - NO.
B. It may be an even number but doesn't have to be - pretty open-ended, but YES (consider 9, 12)
C. It cannot be an even number - consider 9 again - NO.
D. It cannot be a multiple of 6 - consider 12 - NO.
E. It can be a multiple of 6 or an even number, but not both - consider 12 again, NO.

If a number is a multiple of 6, then it must also be a multiple of 3 and it must be an even number. I have a number X which is a multiple of 3. I may assume that: A. It must be an even number. B. It may be an even number but doesn't have to be. C. It cannot be an even number. D. It cannot be a multiple of 6. E. It can be a multiple of 6 or an even number, but not both.

I dont have any OA. just wanted to confirm my answer..

A. It must be an even number.
too absolute B. It may be an even number but doesn't have to be.
moderate reasoning C. It cannot be an even number.
too absolute D. It cannot be a multiple of 6.
too absolute E. It can be a multiple of 6 or an even number, but not both.
too absolute, may be both

A. It must be an even number=> must is too strong.
B. It may be an even number but doesn't have to be=> may be ok.
C. It cannot be an even number=> cannot be too strong.
D. It cannot be a multiple of 6=> cannot be too strong.
E. It can be a multiple of 6 or an even number, but not both=> can be ok, but cannot be both means cannot be a multiple of 6 and even integer. too strong too because all multiples of 6 are even integers.

Originally posted on MIT Sloan School of Management : We are busy putting the final touches on our application. We plan to have it go live by July 15...