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If a rectangular solid that has a square base and a height

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New post 09 May 2006, 19:43
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If a rectangular solid that has a square base and a height of 5 inches has a total volume of 80 cubic inches. What is its total surface area in square inches?

Please explain the answer if you could.Thanks.
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New post 09 May 2006, 19:46
Let each side of square base be x, then surface area of the base would be x^2

Then x^2(5) = 80
x^2 = 16
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New post 09 May 2006, 19:53
MA466 wrote:
If a rectangular solid that has a square base and a height of 5 inches has a total volume of 80 cubic inches. What is its total surface area in square inches?

Please explain the answer if you could.Thanks.


volume = l^2 h = 80
l = 4

total surface area = 2 (lxl) +4 (lxh) = 50 = 80 = 130
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New post 09 May 2006, 19:59
ywilfred wrote:
Let each side of square base be x, then surface area of the base would be x^2

Then x^2(5) = 80
x^2 = 16


oops... total surface area should be 2(16) + 4(4(5)) = 112
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New post 09 May 2006, 20:04
Professor wrote:
MA466 wrote:
If a rectangular solid that has a square base and a height of 5 inches has a total volume of 80 cubic inches. What is its total surface area in square inches?

Please explain the answer if you could.Thanks.


volume = l^2 h = 80
l = 4

total surface area = 2 (lxl) +4 (lxh) = 50 = 80 = 130

oopppssss tooooooooooooooooo...........................

total surface area = 2 (lxl) +4 (lxh) = 32+ 80 = 112
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New post 10 May 2006, 00:34
If a - the length of a side then:
5*a^2=80 => a^2=16 => a=4
Then
S=2*a^2+4*(5*a)= /where a=4/ = 112
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New post 11 May 2006, 00:13
Hi,
It is better to be late than ...:)
The volume of the rectangle = x*x*z, where x – sides of square base and z – height of the rectangle. x^2*5=80, x=4. Total surface area = 4*4*2+4*5*2+4*5*2=112
  [#permalink] 11 May 2006, 00:13
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