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If a sequence of consecutive integers of increasing value

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Director
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If a sequence of consecutive integers of increasing value [#permalink] New post 23 Oct 2006, 01:23
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If a sequence of consecutive integers of increasing value has a sum of 63 and a first term of 6, how many integers are in the sequence?

(A) 11
(B) 10
(C) 9
(D) 8
(E) 7
Manager
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 [#permalink] New post 23 Oct 2006, 01:55
E. 7

63 = (n/2) (2*6+(n-1)*1)

Where n is the number of terms.....

Solving for n, we get n = -18 OR n = 7

Verifying , 6+7+8+9+10+11+12 = 63
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 [#permalink] New post 23 Oct 2006, 02:25
Girikorat, did you set-up that equation or is that a formula you keep in mind? If it's a formula, can you state in general terms? Thanks :)
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Director
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 [#permalink] New post 23 Oct 2006, 16:40
Yes, please explain.

Also, the problem says "consecutive integers". Will this always mean 6,7,8,9 ... or might they mean consecutive even/odd numbers?
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 [#permalink] New post 23 Oct 2006, 18:02
Sum of n terms in an arithmetic series is

N/2(2a+(N-1)d)

where N-- number of terms
a--- 1st term
d----difference.


Also FYI--

N th term is given by

a+(n-1)d
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 [#permalink] New post 23 Oct 2006, 20:22
Code:
Sum of n terms in an arithmetic series is

N/2(2a+(N-1)d)

where N-- number of terms
a--- 1st term
d----difference.


Also FYI--

N th term is given by

a+(n-1)d


Nothing to add :)
  [#permalink] 23 Oct 2006, 20:22
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If a sequence of consecutive integers of increasing value

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