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If a two-digit positive integer has its digits reversed, the

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If a two-digit positive integer has its digits reversed, the [#permalink] New post 27 Dec 2012, 07:29
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If a two-digit positive integer has its digits reversed, the resulting integer differs from the original by 27. By how much do the two digits differ?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 7
[Reveal] Spoiler: OA
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Re: If a two-digit positive integer has its digits reversed, the [#permalink] New post 27 Dec 2012, 07:31
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Walkabout wrote:
If a two-digit positive integer has its digits reversed, the resulting integer differs from the original by 27. By how much do the two digits differ?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 7


Given that (10a + b) - (10b + a) = 27 --> 9a - 9b =27 --> a - b = 3.

Answer: A.
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Re: If a two-digit positive integer has its digits reversed, the [#permalink] New post 13 Oct 2013, 13:45
Bunuel wrote:
Walkabout wrote:
If a two-digit positive integer has its digits reversed, the resulting integer differs from the original by 27. By how much do the two digits differ?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 7


Given that (10a + b) - (10b + a) = 27 --> 9a - 9b =27 --> a - b = 3.

Answer: A.


Do we use 10 because of the tens digit??
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Re: If a two-digit positive integer has its digits reversed, the [#permalink] New post 13 Oct 2013, 13:49
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runningguy wrote:
Bunuel wrote:
Walkabout wrote:
If a two-digit positive integer has its digits reversed, the resulting integer differs from the original by 27. By how much do the two digits differ?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 7


Given that (10a + b) - (10b + a) = 27 --> 9a - 9b =27 --> a - b = 3.

Answer: A.


Do we use 10 because of the tens digit??


Yes, any two-digit integer ab can be expressed as 10a+b, for example: 45 = 10*4 + 5.

The same for 3, 4, 5, ... digit numbers. For example, 4-digit number 5,432 can be written as 5*1,000 + 4*100 + 3*10 + 2 = 5,432.

Hope it's clear.
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Re: If a two-digit positive integer has its digits reversed, the [#permalink] New post 12 Jan 2014, 14:28
Walkabout wrote:
If a two-digit positive integer has its digits reversed, the resulting integer differs from the original by 27. By how much do the two digits differ?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 7



The answer has to be a factor of 27, the only option that's a factor of 27 is 3.

Sice \((10x + y) - (10y + x) = 27\), you can simplify this relationship by subtracting with a common factor --> 9x - 9y = 27 ---> 9(x - y) = 27 ---> here, you already notice that the difference has to be a factor of both 9 and 27, but you can simplify further ---> x - y = 3, and thus we have the answer.

But these last steps are superfluous if you already notice that the answer has to be a factor of 27, this way you save time without having to calculate.
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Re: If a two-digit positive integer has its digits reversed, the [#permalink] New post 18 Feb 2015, 20:57
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Re: If a two-digit positive integer has its digits reversed, the [#permalink] New post 18 Feb 2015, 21:12
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Hi All,

Even though this question might seem a little strange, you do NOT need to do any excessive math to get to the correct answer. With just a bit of 'playing around' you can use 'brute force' to get to the answer.

We're told that a 2-digit number has its digits reversed and the difference between those two numbers is 27.

IF we use....
11 and 11, then the difference is 0 - this is NOT a match

12 and 21, then the difference = 9 - this is NOT a match

13 and 31, then the difference = 18 - this is NOT a match (notice the pattern though? The difference keeps increasing by 9!!!!! I wonder what the next one will be???)

14 and 41, then the difference = 27 = this IS a match

The question asks for the difference in the two DIGITS. The difference between 1 and 4 is 3.

Final Answer:
[Reveal] Spoiler:
A


There are actually several ways to get to this answer: 14 and 41, 25 and 52, 36 and 63, 47 and 74, 58 and 85, 69 and 96.

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Re: If a two-digit positive integer has its digits reversed, the   [#permalink] 18 Feb 2015, 21:12
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