If a wire 27 meters is cut into three pieces of three : DS Archive
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# If a wire 27 meters is cut into three pieces of three

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If a wire 27 meters is cut into three pieces of three [#permalink]

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25 Mar 2008, 14:01
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If a wire 27 meters is cut into three pieces of three different length, what is the length of the longest piece?

(1) The length of the longest piece is twice the length of the shortest piece

(2) The sum of the length of the two shorter pieces is 15
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25 Mar 2008, 14:13
Lets say 3 parts are x (shortest), y(medium), and z(longest). Then x+y+z = 27
Question is asking for value of z.

Statement 1:
Tells us that z=2x, but there is no mention of y in this relation so this statement alone is insufficient.

Statement 2:
Tells us that x+y=15 => z=27-(x+y) = 27-15 = 12.
So this statement alone can answer the question.

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25 Mar 2008, 14:45
abhijit_sen wrote:
Lets say 3 parts are x (shortest), y(medium), and z(longest). Then x+y+z = 27
Question is asking for value of z.

Statement 1:
Tells us that z=2x, but there is no mention of y in this relation so this statement alone is insufficient.

Statement 2:
Tells us that x+y=15 => z=27-(x+y) = 27-15 = 12.
So this statement alone can answer the question.

For Statement 1, only one works: 6, 9, 12. So, I think A is valid as well.
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25 Mar 2008, 14:50
f00kie wrote:
abhijit_sen wrote:
Lets say 3 parts are x (shortest), y(medium), and z(longest). Then x+y+z = 27
Question is asking for value of z.

Statement 1:
Tells us that z=2x, but there is no mention of y in this relation so this statement alone is insufficient.

Statement 2:
Tells us that x+y=15 => z=27-(x+y) = 27-15 = 12.
So this statement alone can answer the question.

For Statement 1, only one works: 6, 9, 12. So, I think A is valid as well.

Yes you are right f00kie. I did not consider putting values into variables.
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25 Mar 2008, 15:19
I said B as well. How would you solve this using equations. If you created a equation out of statement 1 you would get:

s+m+l = 27
l = 2s

3s + m =27.

Then I said insuff.
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25 Mar 2008, 15:23
You just randomly pick some values to satisfy this equation. As 3x is multiple of 3 and so is 27, so y should also be multiple of 3.
Moreover you should also have x<y<2x.
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25 Mar 2008, 15:59
I don't see how GMAT would expect a person to just randomly guess #s here. There has to be a formula trick to this.
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25 Mar 2008, 17:05
f00kie wrote:
abhijit_sen wrote:
Lets say 3 parts are x (shortest), y(medium), and z(longest). Then x+y+z = 27
Question is asking for value of z.

Statement 1:
Tells us that z=2x, but there is no mention of y in this relation so this statement alone is insufficient.

Statement 2:
Tells us that x+y=15 => z=27-(x+y) = 27-15 = 12.
So this statement alone can answer the question.

For Statement 1, only one works: 6, 9, 12. So, I think A is valid as well.

The length numbers do not need to be integers.
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26 Mar 2008, 07:08
Please see my explanation in second post that holds true. Keeping in mind that x, y, and z may or may not be integer. So although 6, 9, 12 are only integer values satisfying the equation, there may be lots of non-integer values e.g. 6.3, 8.1, 12.6 which will be satisfying the equation.

Re: DS gmat prep   [#permalink] 26 Mar 2008, 07:08
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