Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Let S = shortest piece, M = middle piece, and L = longest piece. The stem says that S + M + L = 27 meters.

(1) INSUFFICIENT. The statement says L = 2S. However, the statement says nothing about the length of M. As a result, more than one solution is possible. For example, if S = 6, then L = 12 and M = 9. Or, if S = 5.5, then L = 11 and M = 10.5.

(2) SUFFICIENT. This statement says S + M = 15. If you substitute this equation into the original equation provided in the stem, you have: S + M + L = 27 (original equation) 15 + L = 27 (substitute 15 for "S + M") L = 12 (subtract 15 from both sides)

If a wire 27 meters long is cut into three pieces of three different lengths, what is the length of the longest piece?

Actually one can solve the question without any formula.

(1) The length of the longest piece is twice the length of the shortest piece --> 6+8+12=27 or 5.5+10.5+11=27. Not sufficient.

(2) The sum of the length of the two shorter pieces is 15 meters --> if the sum of the two shorter pieces is 15 meters then longest piece must be 27-15=12. Sufficient.

Re: If a wire 27 meters long is cut into three pieces of three [#permalink]

Show Tags

01 Feb 2012, 15:08

Bunuel wrote:

If a wire 27 meters long is cut into three pieces of three different lengths, what is the length of the longest piece?

Actually one can solve the question without any formula.

(1) The length of the longest piece is twice the length of the shortest piece --> 6+8+12=27 or 5.5+10.5+11=27. Not sufficient.

(2) The sum of the length of the two shorter pieces is 15 meters --> if the sum of the two shorter pieces is 15 meters then longest piece must be 27-15=12. Sufficient.

Answer: B.

Hi Bunnel

I too came up with same solution

But From 2

we know that all three have different lengths and we now know that one of the lengths is 12 and sum of the other two lengths is 15, but now when you consider all 3 lengths they can be

11,3,12--------->Length of longest piece is 12 14,1,12----------->Length of longest piece is 14 13,2,12----------->Length of longest piece is 13

So we do not get a unique solution, so i marked C.......Plz correct me if i am wrong

If a wire 27 meters long is cut into three pieces of three different lengths, what is the length of the longest piece?

Actually one can solve the question without any formula.

(1) The length of the longest piece is twice the length of the shortest piece --> 6+8+12=27 or 5.5+10.5+11=27. Not sufficient.

(2) The sum of the length of the two shorter pieces is 15 meters --> if the sum of the two shorter pieces is 15 meters then longest piece must be 27-15=12. Sufficient.

Answer: B.

Hi Bunnel

I too came up with same solution

But From 2

we know that all three have different lengths and we now know that one of the lengths is 12 and sum of the other two lengths is 15, but now when you consider all 3 lengths they can be

11,3,12--------->Length of longest piece is 12 14,1,12----------->Length of longest piece is 14 13,2,12----------->Length of longest piece is 13

So we do not get a unique solution, so i marked C.......Plz correct me if i am wrong

Thanks in advance

Look at the red part. (2) states this in a different way: The sum of the length of the two SHORTER pieces is 15 meters, so the third one left must be the longest piece.

Re: If a wire 27 meters long is cut into three pieces of three [#permalink]

Show Tags

01 Feb 2012, 17:18

Bunuel wrote:

kotela wrote:

Bunuel wrote:

If a wire 27 meters long is cut into three pieces of three different lengths, what is the length of the longest piece?

Actually one can solve the question without any formula.

(1) The length of the longest piece is twice the length of the shortest piece --> 6+8+12=27 or 5.5+10.5+11=27. Not sufficient.

(2) The sum of the length of the two shorter pieces is 15 meters --> if the sum of the two shorter pieces is 15 meters then longest piece must be 27-15=12. Sufficient.

Answer: B.

Hi Bunnel

I too came up with same solution

But From 2

we know that all three have different lengths and we now know that one of the lengths is 12 and sum of the other two lengths is 15, but now when you consider all 3 lengths they can be

11,3,12--------->Length of longest piece is 12 14,1,12----------->Length of longest piece is 14 13,2,12----------->Length of longest piece is 13

So we do not get a unique solution, so i marked C.......Plz correct me if i am wrong

Thanks in advance

Look at the red part. (2) states this in a different way: The sum of the length of the two SHORTER pieces is 15 meters, so the third one left must be the longest piece.

Does that make sense?

Thanks Bunnel it makes sense

I always make silly mistakes...when i review i almost crack every problem,the problem with me is i am unable to do it during the exam time......Any suggestion please
_________________

I always make silly mistakes...when i review i almost crack every problem,the problem with me is i am unable to do it during the exam time......Any suggestion please

We all do from time to time. It will pass with practice. Just keep paying attention to all the words in the stem/statements. The GMAT questions are very well written and every word has its purpose.
_________________

Re: If a wire 27 meters long is cut into three pieces of three [#permalink]

Show Tags

06 Nov 2014, 07:34

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Re: If a wire 27 meters long is cut into three pieces of three [#permalink]

Show Tags

18 Jan 2015, 05:56

Quote:

If a wire 27 meters long is cut into three pieces of three different lengths, what is the length of the longest piece?

Actually one can solve the question without any formula.

(1) The length of the longest piece is twice the length of the shortest piece --> 6+8+12=27 or 5.5+10.5+11=27. Not sufficient.

Hi,

I didn't consider the decimal option of 5.5+10.5+11=27 and got the answer wrong, as I assumed 6+8+12 is the only option that fits the statement. Not sure how can I avoid this in the exam?

When dealing with DS questions, it helps to be a little bit cynical/suspicious. Ask yourself: "What do I REALLY KNOW? What specific details did the prompt give me and what did it NOT tell me?" In real life, there are plenty of situations in which you're not dealing with integers (the bill at a restaurant, credit card/utility bills, distance traveled, etc.), so non-integers isn't a strange concept. You have to show how THOROUGH your thinking is to pick up these points - the "math work" isn't normally that difficult, but you have to be constantly thinking about the possibilities to make sure that you have the correct answer.

There are a couple of problems with what you're typed out (although most of the individual 'pieces' of your work are fine).

Here's what's "fine": 1) Calling the 3 segments A, B and C 2) Stating A+B+C = 27 3) A > B > C (since the three segments are DIFFERENT lengths) 4) A = 2C (from Fact 1) 5) The substituion: A+B+C = 27 A = 2C 2C+B+C = 27 3C + B = 27

Here's what's INCORRECT: 1) The algebra after the substitution...Dividing both sides by 3 will NOT get you the result that you typed:

3C+B = 27

C + (B/3) = 9 is the correct result

2) The two "short" segment CANNOT be the same length (remember, they're DIFFERENT lengths). 3) The shortest segment CANNOT be 9. If it were, then the other two pieces would be GREATER than 9 and the total would be GREATER than 27.

Happy New Year everyone! Before I get started on this post, and well, restarted on this blog in general, I wanted to mention something. For the past several months...

It’s quickly approaching two years since I last wrote anything on this blog. A lot has happened since then. When I last posted, I had just gotten back from...

Post-MBA I became very intrigued by how senior leaders navigated their career progression. It was also at this time that I realized I learned nothing about this during my...