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Re: If a1, a2, a3, ..., an, ... is a sequence such that an = 2n [#permalink]

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29 Jan 2016, 05:35

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Re: If a1, a2, a3, ..., an, ... is a sequence such that an = 2n [#permalink]

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16 Jul 2016, 00:15

eybrj2 wrote:

If a1, a2, a3, ..., an, ... is a sequence such that an = 2n for all n>= 1, is ai greater than aj?

(1) i is add and j is even.

(2) i^2 > j^2

(1) i is odd and j is even. Not Sufficient. We don't know whether the odd or the even is bigger in magnitude

(2) i^2 > j^2 Sufficient :- Since numbers are non negative it means there is no surprises of mistakenly squaring a smaller negative. A bigger squared value means a bigger base value so i>j

Sufficient

Answer is B
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Re: If a1, a2, a3, ..., an, ... is a sequence such that an = 2n
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16 Jul 2016, 00:15

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