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If ab≠0 and points (-a,b) and (-b,a) are in the same

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Re: DS : GMATPrep : Quadrant [#permalink] New post 03 Nov 2008, 02:22
kandyhot27 wrote:
amitdgr wrote:
If ab is not 0 and points (-a,b) and (-b,a) are in the same quadrant of the xy-plane, is point (-x,y) in this same quadrant ?

(1) xy > 0
(2) ax > 0


IMO C

From what is given, it is clear a and b have the same sign (ie either both are positive or both are negative)

(i)
Informs that x and y have the same sign
But it is not clear their relationship with a or b and hence can't say which quadrant do they belong.

(ii)
This informs that a and x are of the same sign also (ie either both of them are negative or both of them are positive)
ii alone does not inform the relationship with y

However, combining them, gives a, b, x and y are all of the same sign. Thus (-x,y) will be in the same quadrant as (-a, b) and (-b, a)

OA ?


OA is C .... what i don't understand is how you determined the portion in red ...
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Re: DS : GMATPrep : Quadrant [#permalink] New post 03 Nov 2008, 10:59
amitdgr wrote:
From what is given, it is clear a and b have the same sign (ie either both are positive or both are negative)
OA is C .... what i don't understand is how you determined the portion in red ...


Since (-a,b) and (-b,a) lie in the same quadrant and x co-ordinates of these two points are -a and -b, this means, -a and -b lie on the same side of x-axis (either positive or negative) and hence both a and b will have the same sign.
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Re: DS : GMATPrep : Quadrant [#permalink] New post 04 Nov 2008, 02:55
If ab is not 0 and points (-a,b) and (-b,a) are in the same quadrant of the xy-plane, is point (-x,y) in this same quadrant ?

(1) xy > 0
(2) ax > 0

-----------------------

I got C too, here is my approach.

First, I forced a to be -1 and be to be -2 in order to satisfied (-a,b) and (-b,a) are in same quadrant.
so we got (--1,-2) and (--2,-1) --> (1,-2) and (2,-1) which lies in Q4

stmt 1: xy>0, xy must have same sign so if x and y are positive, it makes (-x,y) to be in Q2 --> this case No
if x and y are nagative, it make (--x,,-y) to be in Q4 --> this case yes
so stmt 1 insuff

stmt 2: ax>o, since we know that a is negative from the number we forced in the beginning, then we know that x is nagative too, however, we don't know about y --> insuff

combine both stmt, we know from 2) that x is negative so y in stmt 1) have to be nagative. So it definitely in Q4 as same as (a,b)
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Coordinate Plane [#permalink] New post 08 Nov 2008, 03:39
If ab in not equal to 0. And points (-a,b) & (-b, a) are in the same quadrant, is (-x, y) in teh same quadrant?

1. xy > 0
2. ax >0
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Re: Coordinate Plane [#permalink] New post 08 Nov 2008, 04:02
if ab is not equal to 0, then both a and b are not equal to 0
if (-a,b) & (-b, a) are in the same quadrant, then a>0 and b>0

1. xy>0, ---> both x,y>0 or both x,y<0, not suff
2. ax>0, ---> x>0, but we dono y, not suff

together, both x,y>0, suff

OA is C
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DS: xy-plane [#permalink] New post 03 Mar 2009, 17:37
if ab#0 and points (-a,b) and (-b,a) are in the same quadrant of the xy-plane, is (-x,y) in this same quadrant?

1) xy>0
2) ax>0

_______________________________________________________________________________________________

My thought process is stuck on stmt 2, how can I determine what a is given the points? why can't a but a negative therefore making it a positive as a (-a,b)?

Thanks,
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Re: DS: xy-plane [#permalink] New post 03 Mar 2009, 18:07
ans: C

to have -a,b and -b,a in same quadrant, a and b should be positive.

from b, ax>0, (+a)x>0, x should be positive, we dont know about y so insufficient
from a, xy>0, x and y should be +ve or x and y both should be -ve

combing a and b, x and y should be +ve, hence -x,y is in the same quadrant as -a,b
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Re: DS: xy-plane [#permalink] New post 03 Mar 2009, 18:13
C.

Given: ab#0 and points (-a,b) and (-b,a) are in the same quadrant
Implies that either both a & b are -ve or both a & b are +ve.

1) either x & y can both be +ve or both be -ve. so we can not decide between 1st and 3rd quadrant
2) we know that a and x have same sign, but unable to determine if they are in same quadrant

together:
a,x and y all have same sign => are in same quadrant ( as "b" has same sign as "a")
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Re: DS: xy-plane [#permalink] New post 03 Mar 2009, 18:28
Thanks for the explanation!
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GMAT Prep DS - Quandrants [#permalink] New post 17 Mar 2009, 11:43
If ab is not equal to zero and points (-a,b) and (-b,a) are in the same quadrant of the xy plane, is point (-x,y) in the same quadrant?

1) xy>0
2) ax>0
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Re: GMAT Prep DS - Quandrants [#permalink] New post 17 Mar 2009, 14:27
(a and x) and (b and y) should both be -ve or +ve for them to lie in the same quadrent.
consider xy>0:

either both x and y are -ve or both x and y are +ve

consider ax>0:

either both a and x are -ve or both x and y are +ve

I guess answer is E.
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Re: GMAT Prep DS - Quandrants [#permalink] New post 17 Mar 2009, 16:07
OA is C.

Taking statment 1 and 2 together:

a, x and y all have to be the same sign, either positive or negative.

If its negative then (-x,y) should be positive and negative respectively, just like a and b.

If its positive then (-x,y) should be negative and positive respectively, just like a and b.

Hence, (-x,y) is in the same quadrant as (-a, b) ann (-b, a) taking st1 and st2 together.

Does this make sense?
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coordinate geometry problem [#permalink] New post 09 Jun 2009, 19:33
Hey guys, was wondering if anyone had a good method for this problem:

ab is not equal to zero. Points (-a,b) and (-b,a) are in the same quadrant of the xy- plane, is point (-x,y) in this same quadrant?

(1) xy is greater than 0
(2)ax is greater than 0


answer: C.
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Re: coordinate geometry problem [#permalink] New post 10 Jun 2009, 15:29
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Let me give this a try.
Given:
ab is not equal to zero.
Points (-a,b) and (-b,a) are in the same quadrant of the xy- plane.

Here are the four quadrants:
\[
\begin{array}{c|c}
II & I \\
\hline
III & IV
\end{array}
\]


As the two points are in the same quadrant a and b have the same signs. Lets look at two scenarios.
1. a and b are positive numbers e.g. a = 5 and b = 2 then
(-a,b) = (-5,2) and (-b,a) = (-2,5) Here both the points lie in Quadrant II
2. a and b are negative numbers e.g. a = -4 and b = -3 then
(-a,b) = (4,-3) and (-b,a) = (3,-4) Here both the points lie in Quadrant IV

The question is asking us if the point (-x,y) in this same quadrant as the above two points? i.e the point (-x,y) would have to be in Quadrant II when a and b are positive or the point (-x,y) would have to be in Quadrant IV when a and b are negative. This would mean that x and y would have to share the same sign as a and b to belong in the same quadrant.

Lets look at statement 1:
xy is greater than 0
=> x and y are both positive or x and y are both negative.
=> This atleast tells us that the point in either in Quadrant II or IV.
=> We don't have any relationship of x or y to a or b. Hence Not Sufficient.

Lets look at statement 2:
ax is greater than 0
=> a and x are both positive or a and x are both negative.
=> This tells us that x shares the same sign as a (and b) but we still don't know anything about y. Hence Not sufficient.

Looking at them together;
1 tells us x and y have the same sign.
2 tells us x as the same sign as a and b. Which means y as the same sign as a and b.
=> x and y are positive when a and b are positive or x and y are negative when a and b are negative.
Hence, the point (-x,y) lies on the same quadrant as the points (-a,b) and (-b,a).

Sufficient.
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Re: coordinate geometry problem [#permalink] New post 10 Jun 2009, 18:56
This is a good question and gr8 explanation.Thx
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DS Question [#permalink] New post 28 Jun 2009, 13:19
Folks here is a question from GMATPrep . Please explain the answer.. thanks much

if ab \neq 0 and (-a, b) and (-b, a) are in the same quadrent of the xy plane, is point( -x, y) in this same quadrent

1) xy > 0
2) ax > 0
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Re: DS Question [#permalink] New post 28 Jun 2009, 13:38
ans is C

for -a, b and -b, a to be in same quadrant, a and b must have the same sign.

same goes for x and y. X must have the same sign as Y, and they both must also have the same sign as a and b to be in that same quadrant.

the two statements together only can ensure this.
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Re: DS Question [#permalink] New post 28 Jun 2009, 17:03
Ans- C
A different approach.
The points (-a,b) and (-b,a) are in the same quadrant. There is no harm in thinking that both of these are same point and we are just representing it with different variables.
If these are same point then
-a = -b and b = a which means that a and be both should have the same sign.

Stmt 1.
XY > 0
tells that either X and Y are both +ve or both -ve.we are not sure
So we can not tell where is (-x,y) as it can be 1st or 3rd quadrant.

stmt 2.
ax > 0
if a = +ve means x = +ve
if a = -ve means x = -ve
no suff.

Combine,
we can say that a and y have the same sign and the sign of X will be same as that of Y (which we already concluded).
Hence suff.
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Re: DS Question [#permalink] New post 02 Jul 2009, 09:18
Hi all thanks for the explanations but i still do not get the questiounderstand .. Let me try and explain where my head is it

1) -a and b to be in the same quadrent - could it be that-a = -3 and b = 3
Is this what you mean by both points having the same sign ? Can some one explain with a diagram please..

Regards
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GMAT Prep - DS 6 [#permalink] New post 31 Aug 2009, 19:33
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