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If ab>0, does (a+2)(b+2) = 4? (1) ab = -2(a+b) (2) a=b

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If ab>0, does (a+2)(b+2) = 4? (1) ab = -2(a+b) (2) a=b [#permalink] New post 10 Sep 2005, 14:06
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A
B
C
D
E

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100% (01:54) correct 0% (00:00) wrong based on 4 sessions
If ab>0, does (a+2)(b+2) = 4?

(1) ab = -2(a+b)
(2) a=b

(Never mind, I realize what I did wrong...)
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 [#permalink] New post 10 Sep 2005, 15:45
Yeah, OA is A.

I of course went through a whole elaborate solve method for B in which I assumed the solution while trying to determine it. Bad idea. :oops:
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 [#permalink] New post 02 Oct 2005, 12:24
why is it A?

Always attempt to give an explanation if you can....just so people can learn from it...

here is how I was thinking....

If ab>0, does (a+2)(b+2) = 4?

(1) ab = -2(a+b)
(2) a=b

so I re-arrange the stem (a+b)(4)=4...

so we need to know is if (a+b)=1

(1) says ab=-2(a+b)

then (we know ab>0) -ab/2=(a+b) or -1/2=[(a+b)/ab]...clearly (a+b) is not equal to 1...so (1) is sufficient...

(2) a=b
we know that a=b, well we really need to know if a=1 or 1/2 or b=1 or 1/2...this doesnt say much about a or b....so Insufficient...
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 [#permalink] New post 02 Oct 2005, 13:56
fresinha12 wrote:

so I re-arrange the stem (a+b)(4)=4...



how did you re-arrange (a+2)(b+2)=4 to (a+b)(4)=4?

Am I missing something?

I choose (D) (though I see the OA mentioned as A)


stem asks whether (a+2)(b+2)=4?

this can be re-arranged to ab+2a+2b=0

statement I: ab=-2(a+b), which can be rewritten to ab+2a+2b=0, thus sufficient.

statement II: a=b. is (a+2)(a+2)=4? (a+2)^2=4, or a+2=+2 or -2, therefore a = -4, since if a+2=+2, a would equal zero, and ab would not be > 0. since a = b, a = b = -4. therefore (-4+2)(-4+2)=4. Sufficient.
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 [#permalink] New post 02 Oct 2005, 14:06
Chets, can you explain how we can just solve the equation (a+2)(b+2) = 4 when the stem says we are not sure if (a+2)(b+2) is indeed 4.
From 2) all you really get is (a+2)(a+2) which is (a+2)^2.. .which does not mean that the eqn is necessarily = 4. a can be anything.... 1,2, -5, 3/4, Depending on what value of a you select ... (a+2)^2 can have any value. So insufficient. All it means is that for the condition to be true, we need a=2 and a=b does not tell you that.
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 [#permalink] New post 02 Oct 2005, 15:11
vikramm wrote:
Chets, can you explain how we can just solve the equation (a+2)(b+2) = 4 when the stem says we are not sure if (a+2)(b+2) is indeed 4.
From 2) all you really get is (a+2)(a+2) which is (a+2)^2.. .which does not mean that the eqn is necessarily = 4. a can be anything.... 1,2, -5, 3/4, Depending on what value of a you select ... (a+2)^2 can have any value. So insufficient. All it means is that for the condition to be true, we need a=2 and a=b does not tell you that.


Good call, statement II doesn't suffice. So I guess A it is!
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 [#permalink] New post 02 Oct 2005, 16:20
It is A,

Probably a question asked at the end of a GMAT exam. Possibility that it is an experimental question...
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Re: DS - never mind, I realize what I did wrong [#permalink] New post 03 Oct 2005, 02:01
coffeeloverfreak wrote:
If ab>0, does (a+2)(b+2) = 4?

(1) ab = -2(a+b)
(2) a=b

(Never mind, I realize what I did wrong...)


My answer is A. Here is the explanation.

(a+2) (b+2) = ab + 2a + 2b + 4
=> ab + 2(a+b) + 4

From statement 1 we have ab = -2(a+b), substituting in above equn,
-2(a+b) + 2(a+b) + 4
= 4 , So A is sufficient to answer the solution.

From statement 2, we get a = b applying this in original equn we get
a^2+4+4a , here the value will differ for every value of A. Hence B is not sufficient.

Thanks
Sreeni
Re: DS - never mind, I realize what I did wrong   [#permalink] 03 Oct 2005, 02:01
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