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If an integer n is divisible by both 6 and 8, then it must

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If an integer n is divisible by both 6 and 8, then it must [#permalink] New post 12 Sep 2006, 11:21
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If an integer n is divisible by both 6 and 8, then it must also be divisible by which of the following?
(A) 10
(B) 12
(C) 14
(D) 16
(E) 18
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 [#permalink] New post 12 Sep 2006, 11:26
B IS MY ANSWER

FOR an unknown to be devisible by 6 and 8 then its prime factors include but not limited to

2^3 and 3

so it could be divisible by any number that has a combination of the above prime factors

only 12 = 2^2*3 suits this criteria
  [#permalink] 12 Sep 2006, 11:26
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If an integer n is divisible by both 6 and 8, then it must

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