Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: If b< 1 and 2x-b = 0, which of the following must be true? [#permalink]
09 Apr 2015, 20:46

1

This post received KUDOS

Expert's post

nphatak wrote:

Well you see its not finding the roots that is the problem. I can find the conditions under which the inequality will hold. Its the answer choices that I said were confusing. The answer choice a=0 is true, the inequality will be 0. And when you are asked what must be true, you are like..yeah at a = 0 this is true. But the question is not if its true at one value, the question is which answer choice covers all the possible values. Not one! I am probably not able to explain what the confusion is.

If a^5 ≤ a, which of the following must be true?

I. –1 ≤ a ≤ 0 II. a=0 III. 0 ≤ a ≤ 1

A. None of the above B. I only C. II only D. III only E. I and III only

So when you solve the inequality, you get a <= -1 OR 0 <= a <= 1. a is either less than -1 or it is between 0 and 1.

Let's see what each statement says.

I. –1 ≤ a ≤ 0 This says that a must be between -1 and 0. True or False? False

II. a=0 This says that a must be 0. True or False? False. a is either less than -1 or it is between 0 and 1.

III. 0 ≤ a ≤ 1 This says that a must lie between 0 and 1. True or False? False. a is either less than -1 OR it is between 0 and 1.

Now, think if there were another statement IV. a < 2 This says a must be less than 2. True or False? True. a is either less than -1 OR it is between 0 and 1. In any case, it will always be less than 2.

By the way, it is not a trick. It is based on logic and can easily be tested on GMAT. _________________

Re: Prob from Kaplan Diagnostic test [#permalink]
06 Dec 2009, 11:13

tania wrote:

For the following question, it is indicated that option D is correct.

I am not able to understand why ? can anyone explain to me in detail about this one

if b< 1 and 2x-b = 0, which of the following must be true?

A.X>-1 B.x<-2 C.X=2 D.X<3 E.X>3

Regards, Tania

The two statements we have been given are :

1) b < 1

2) 2x - b = 0

Now notice that all the answer choices ask us something relating to the value of 'x'. This is our cue for rearranging the given information so that we can cross check its validity with the answer choices.

Let us write the equation as : x = b/2

Since we know that 'b < 1', we can safely conclude that x must be less that 1/2 or 'x < 0.5'

Now let us compare the answer choices to see which one of them must be true with the information we have at hand.

(A) x > -1 --> We know that x < 0.5 but there is no restriction on its lower limit. Thus it can hold values that are less than -1. Hence this statement is not necessarily true.

(B) x < -2 --> Again since x can hold any values less than 0.5 (such as 0, -0.5 etc.) this statement is not always true.

(C) x = 2 --> Since we know that x < 0.5, this statement can never be true.

(D) x < 3 --> If x < 0.5, then x MUST be less than 3. Therefore this statement MUST be true.

(E) x > 3 --> Since we know that x < 0.5, this statement can never be true.

Re: Prob from Kaplan Diagnostic test [#permalink]
26 Oct 2012, 21:12

Hello All,

X < 1/2 is correct, two answer choices seems to be correct B.x<-2 D.X<3 It is not given than X is a postive or negative, integer or fraction. In my opinion, if we consider D it can have possible answer as X = 2 or X = 1, but X has to be less than 1/2. If we consider X < -2 for all values of X, X < 1/2 holds true. Hence my answer was B.

Re: Prob from Kaplan Diagnostic test [#permalink]
26 Oct 2012, 21:57

pritish2301 wrote:

Hello All,

X < 1/2 is correct, two answer choices seems to be correct B.x<-2 D.X<3 It is not given than X is a postive or negative, integer or fraction. In my opinion, if we consider D it can have possible answer as X = 2 or X = 1, but X has to be less than 1/2. If we consider X < -2 for all values of X, X < 1/2 holds true. Hence my answer was B.

Please feel free to correct me.

REgards, Pritish

Hi Pritish,

Question says : if b< 1 and 2x-b = 0 , which of the following must be true?or in simple words , "if x<1/2 , which of the following must be true?"

Option B doesnt hold good for any value of x where, \(-2 <=x <1/2\)

Consider for example, if x =0, x<1/2 is true but x <-2 is not true Hence B can not be the answer.

On the other hand, for option D as others have pointed out correctly. Since x <1/2 and 1/2 <3 this implies that x <3 . This would be true for any value of x that satisfies x<1/2.

Re: Prob from Kaplan Diagnostic test [#permalink]
26 Oct 2012, 22:22

Vips0000 wrote:

pritish2301 wrote:

Hello All,

X < 1/2 is correct, two answer choices seems to be correct B.x<-2 D.X<3 It is not given than X is a postive or negative, integer or fraction. In my opinion, if we consider D it can have possible answer as X = 2 or X = 1, but X has to be less than 1/2. If we consider X < -2 for all values of X, X < 1/2 holds true. Hence my answer was B.

Please feel free to correct me.

REgards, Pritish

Hi Pritish,

Question says : if b< 1 and 2x-b = 0 , which of the following must be true?or in simple words , "if x<1/2 , which of the following must be true?"

Option B doesnt hold good for any value of x where, \(-2 <=x <1/2\)

Consider for example, if x =0, x<1/2 is true but x <-2 is not true Hence B can not be the answer.

On the other hand, for option D as others have pointed out correctly. Since x <1/2 and 1/2 <3 this implies that x <3 . This would be true for any value of x that satisfies x<1/2.

hope it helps.

As you mentioned "Consider for example, if x =0, x<1/2 is true but x <-2 is not true Hence B can not be the answer."

If we chose option B X can never be equal to 0, but if X<3 there is a possibility that X can be 0. Right?

Re: Prob from Kaplan Diagnostic test [#permalink]
27 Oct 2012, 20:39

pritish2301 wrote:

Vips0000 wrote:

pritish2301 wrote:

Hello All,

X < 1/2 is correct, two answer choices seems to be correct B.x<-2 D.X<3 It is not given than X is a postive or negative, integer or fraction. In my opinion, if we consider D it can have possible answer as X = 2 or X = 1, but X has to be less than 1/2. If we consider X < -2 for all values of X, X < 1/2 holds true. Hence my answer was B.

Please feel free to correct me.

REgards, Pritish

Hi Pritish,

Question says : if b< 1 and 2x-b = 0 , which of the following must be true?or in simple words , "if x<1/2 , which of the following must be true?"

Option B doesnt hold good for any value of x where, \(-2 <=x <1/2\)

Consider for example, if x =0, x<1/2 is true but x <-2 is not true Hence B can not be the answer.

On the other hand, for option D as others have pointed out correctly. Since x <1/2 and 1/2 <3 this implies that x <3 . This would be true for any value of x that satisfies x<1/2.

hope it helps.

As you mentioned "Consider for example, if x =0, x<1/2 is true but x <-2 is not true Hence B can not be the answer."

If we chose option B X can never be equal to 0, but if X<3 there is a possibility that X can be 0. Right?

Hi Pritish, You are getting confused here - the reasoning follows through question stem first - question says if x<1/2 then which of the following must be true - This means x<1/2 is taken for granted. that is our scope. period.

now within this scope we need to find the answer. You dont choose option first and then try to fit in question, but u read option first, define the limit and then consider and choose options. Hope it is clear. Now click kudos _________________

Re: Prob from Kaplan Diagnostic test [#permalink]
29 Oct 2012, 02:28

Expert's post

pritish2301 wrote:

Hello All,

X < 1/2 is correct, two answer choices seems to be correct B.x<-2 D.X<3 It is not given than X is a postive or negative, integer or fraction. In my opinion, if we consider D it can have possible answer as X = 2 or X = 1, but X has to be less than 1/2. If we consider X < -2 for all values of X, X < 1/2 holds true. Hence my answer was B.

Please feel free to correct me.

REgards, Pritish

Notice that we are asked "which of the following MUST be true?" not COULD be true.

Now, we know that x<1/2, thus x<3 is always true.

Is x<-2 always true? No, if x=0, then x<-2, won't be true, therefore this option is not always true.

Re: If b< 1 and 2x-b = 0, which of the following must be true? [#permalink]
14 Jul 2014, 13:17

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Re: If b< 1 and 2x-b = 0, which of the following must be true? [#permalink]
08 Apr 2015, 19:58

So I was getting confused here especially in comparison to this problem

If a^5 ≤ a, which of the following must be true?

I. –1 ≤ a ≤ 0 II. a=0 III. 0 ≤ a ≤ 1

A. None of the above B. I only C. II only D. III only E. I and III only

Here the answer is A, because of the two possible options II and III, III cannot be right because we can think of -2 and find it to satisfy the original condition and -2 doesn't fall in this range. Although II is true, there are other numbers that satisfy the condition as well.

When I looked at this problem, I am like the correct answer should be x <= 1/2. But those choices were there. The answer was totally unexpected X<3, cause I though how about x = 1, 2 or some other value between 1/2 and 3. These values don't satisfy the condition, then how is it true. This is what I have come up with, especially dealing with inequality problems, try to find a number (outside the range given in the answer choice) and see if it satisfies the question stem. If there is none, then you have the right answer. So for eg. looking at x<3, there is no value of x>=3 that would satisfy the Question stem and hence incorrect.

This is quite tricky to wrap your head around. Very tricky! hopefully this will help me in the future.

Re: If b< 1 and 2x-b = 0, which of the following must be true? [#permalink]
08 Apr 2015, 21:13

nphatak wrote:

So I was getting confused here especially in comparison to this problem

If a^5 ≤ a, which of the following must be true?

I. –1 ≤ a ≤ 0 II. a=0 III. 0 ≤ a ≤ 1

A. None of the above B. I only C. II only D. III only E. I and III only

Here the answer is A, because of the two possible options II and III, III cannot be right because we can think of -2 and find it to satisfy the original condition and -2 doesn't fall in this range. Although II is true, there are other numbers that satisfy the condition as well.

When I looked at this problem, I am like the correct answer should be x <= 1/2. But those choices were there. The answer was totally unexpected X<3, cause I though how about x = 1, 2 or some other value between 1/2 and 3. These values don't satisfy the condition, then how is it true. This is what I have come up with, especially dealing with inequality problems, try to find a number (outside the range given in the answer choice) and see if it satisfies the question stem. If there is none, then you have the right answer. So for eg. looking at x<3, there is no value of x>=3 that would satisfy the Question stem and hence incorrect.

This is quite tricky to wrap your head around. Very tricky! hopefully this will help me in the future.

Hey nphatak...Greetings!!!

I'm a little confused about the example you gave and specially the answer choices. Is this question a standard GMAT question. I don't think the GMAT tries to trick you this way or is it possible

Re: If b< 1 and 2x-b = 0, which of the following must be true? [#permalink]
09 Apr 2015, 01:58

Ashishmathew01081987 wrote:

nphatak wrote:

So I was getting confused here especially in comparison to this problem

If a^5 ≤ a, which of the following must be true?

I. –1 ≤ a ≤ 0 II. a=0 III. 0 ≤ a ≤ 1

A. None of the above B. I only C. II only D. III only E. I and III only

Here the answer is A, because of the two possible options II and III, III cannot be right because we can think of -2 and find it to satisfy the original condition and -2 doesn't fall in this range. Although II is true, there are other numbers that satisfy the condition as well.

When I looked at this problem, I am like the correct answer should be x <= 1/2. But those choices were there. The answer was totally unexpected X<3, cause I though how about x = 1, 2 or some other value between 1/2 and 3. These values don't satisfy the condition, then how is it true. This is what I have come up with, especially dealing with inequality problems, try to find a number (outside the range given in the answer choice) and see if it satisfies the question stem. If there is none, then you have the right answer. So for eg. looking at x<3, there is no value of x>=3 that would satisfy the Question stem and hence incorrect.

This is quite tricky to wrap your head around. Very tricky! hopefully this will help me in the future.

Hey nphatak...Greetings!!!

I'm a little confused about the example you gave and specially the answer choices. Is this question a standard GMAT question. I don't think the GMAT tries to trick you this way or is it possible

it's not a tricky question , trust me . whenever you face such inequalities , first thing to do is to draw their roots on number line .

\(a^5-a <=0\) \(a(a^4-1) <=0\)

root are -1, 0 , 1 now as shown in attached image you can find the regions where this inequality holds . and clearly say that answer is A .

Attachments

gmatclub.jpg [ 24.36 KiB | Viewed 588 times ]

_________________

Thanks, Lucky

_______________________________________________________ Kindly press the to appreciate my post !!

Re: If b< 1 and 2x-b = 0, which of the following must be true? [#permalink]
09 Apr 2015, 15:49

Well you see its not finding the roots that is the problem. I can find the conditions under which the inequality will hold. Its the answer choices that I said were confusing. The answer choice a=0 is true, the inequality will be 0. And when you are asked what must be true, you are like..yeah at a = 0 this is true. But the question is not if its true at one value, the question is which answer choice covers all the possible values. Not one! I am probably not able to explain what the confusion is.

If a^5 ≤ a, which of the following must be true?

I. –1 ≤ a ≤ 0 II. a=0 III. 0 ≤ a ≤ 1

A. None of the above B. I only C. II only D. III only E. I and III only

Re: If b< 1 and 2x-b = 0, which of the following must be true? [#permalink]
10 Apr 2015, 06:40

VeritasPrepKarishma wrote:

nphatak wrote:

Well you see its not finding the roots that is the problem. I can find the conditions under which the inequality will hold. Its the answer choices that I said were confusing. The answer choice a=0 is true, the inequality will be 0. And when you are asked what must be true, you are like..yeah at a = 0 this is true. But the question is not if its true at one value, the question is which answer choice covers all the possible values. Not one! I am probably not able to explain what the confusion is.

If a^5 ≤ a, which of the following must be true?

I. –1 ≤ a ≤ 0 II. a=0 III. 0 ≤ a ≤ 1

A. None of the above B. I only C. II only D. III only E. I and III only

So when you solve the inequality, you get a <= -1 OR 0 <= a <= 1. a is either less than -1 or it is between 0 and 1.

Let's see what each statement says.

I. –1 ≤ a ≤ 0 This says that a must be between -1 and 0. True or False? False

II. a=0 This says that a must be 0. True or False? False. a is either less than -1 or it is between 0 and 1.

III. 0 ≤ a ≤ 1 This says that a must lie between 0 and 1. True or False? False. a is either less than -1 OR it is between 0 and 1.

Now, think if there were another statement IV. a < 2 This says a must be less than 2. True or False? True. a is either less than -1 OR it is between 0 and 1. In any case, it will always be less than 2.

By the way, it is not a trick. It is based on logic and can easily be tested on GMAT.

Thanks a lot Karishma! So the correct answer choice should cover all the possible values of a, right? The way I was interpreting this question was, which of this must be true = any subset of all the possible values has to be true and I marked that answer. Its just a failure in my understanding these kind of questions.

gmatclubot

Re: If b< 1 and 2x-b = 0, which of the following must be true?
[#permalink]
10 Apr 2015, 06:40

MBA Acceptance Rate by Country Most top American business schools brag about how internationally diverse they are. Although American business schools try to make sure they have students from...

McCombs Acceptance Rate Analysis McCombs School of Business is a top MBA program and part of University of Texas Austin. The full-time program is small; the class of 2017...