If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the : Quant Question Archive [LOCKED]
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 18 Jan 2017, 01:34

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the

Author Message
Senior Manager
Joined: 31 Jul 2006
Posts: 440
Followers: 3

Kudos [?]: 44 [0], given: 0

If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the [#permalink]

### Show Tags

28 Sep 2006, 06:27
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If BE CD, and BC = AB = 3, AE = 4 and CD = 10, what is the area of trapezoid BEDC?

Attachments

mgmat-geo1.GIF [ 5.09 KiB | Viewed 1103 times ]

Senior Manager
Joined: 14 Aug 2006
Posts: 363
Followers: 1

Kudos [?]: 45 [0], given: 0

### Show Tags

28 Sep 2006, 08:23
There are two similar triangles in there Tri ABE and Tri ACD

The sides are then proportional.. which means AB/AC = AE/AD = BE /CD

3/6 = x/ 10. so X is 5 (3-4-5 triangle => right triangle)

Area of the trapezoid = Area of the larger triangle - smaller triangle

= 1/2*6 * 8 - 1/2* 4*3
= 24 - 6 = 18

So Ans. B
Senior Manager
Joined: 31 Jul 2006
Posts: 440
Followers: 3

Kudos [?]: 44 [0], given: 0

### Show Tags

28 Sep 2006, 08:48
gk3.14 wrote:
There are two similar triangles in there Tri ABE and Tri ACD

The sides are then proportional.. which means AB/AC = AE/AD = BE /CD

3/6 = x/ 10. so X is 5 (3-4-5 triangle => right triangle)

Area of the trapezoid = Area of the larger triangle - smaller triangle

= 1/2*6 * 8 - 1/2* 4*3
= 24 - 6 = 18

So Ans. B

great explanation. thank you
Senior Manager
Joined: 28 Aug 2006
Posts: 306
Followers: 13

Kudos [?]: 150 [0], given: 0

### Show Tags

29 Sep 2006, 00:28
Clearly both ACD and ABE are right angled triangles.

Area of ACD = 1/2 x 6 x 8 = 24
Area of ABE = 1/2 x 3 x 4 = 6

So area of Trapezium = 24-6 = 18.

Since BE || CD and C bisects AB, obviously D bisects AE
_________________

Last edited by cicerone on 25 Sep 2008, 00:12, edited 1 time in total.
Current Student
Joined: 29 Jan 2005
Posts: 5238
Followers: 25

Kudos [?]: 377 [0], given: 0

### Show Tags

29 Sep 2006, 06:50
cicerone wrote:
Clearly both ACD and ABE are right angled triangles.

Area of ACD = 1/2 x 6 x 8 = 24
Area of ABE = 1/2 x 3 x 4 = 6

So area of Trapezium = 24-6 = 18.

Since BE || CD and C bisects AB, obviously D bisects AE

Nice catch Cicerone. That made the problem a whole lot easier.

AE must equal ED because BE is parallel to CD.
29 Sep 2006, 06:50
Display posts from previous: Sort by