sumit88 wrote:

Hello qoofi,

Please explain me more clearer.

Please check I dont get the answer of this question,

If both 5^2 and 3^3 are factors of n x (2^5) x (6^2) x (7^3) :

It means that n*2^5*6^2*7^3 his number is dicvisible by these 2 factors.

If it is divisible so we can write the equation as,

n*5^2*6^2*7^3/5^2*3^3

= n*5^2*(2^2*3^2) *7^3/5^2*3^3=so after this how to get the answer I dont get it.

Please explain me.

First, if a number, lets say X, is a factor of another number, lets say Y . Then Y is divisible by X In the question, both 5^2 and 3^3 are factors of n x (2^5) x (6^2) x (7^3), so n x (2^5) x (6^2) x (7^3) must be divisible by 5^2 and 3^3

we can rewrite n x (2^5) x (6^2) x (7^3) as n x (2^5) x (2^2) x (3^2) x (7^3)

so to make (2^5) x (2^2) x (3^2) x (7^3) divisible by 5^2 and 3^3, we need 5^2 and 3^1

( if Y is divisible by X, then all prime factors of X must also be prime factors of Y)so n= 5^2 and 3^1 which equals 75.

hope you find it helpful.

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