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# If both x and y are nonzero numbers, what is the value of

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Manager
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If both x and y are nonzero numbers, what is the value of [#permalink]  26 Oct 2007, 18:46
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If both x and y are nonzero numbers, what is the value of y/x ?
(1) x = 6
(2) y^2 = x^2

Manager
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[#permalink]  26 Oct 2007, 19:37
statement 1 is insufficient because you need to know the value of y

statement 2 is insufficient because y and x dont have to be equal, one could be negative and the other could be positive.

together, if x=6, then you know that y^2 = 36 but y could be 6 or -6, so still insufficient.
E
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[#permalink]  28 Oct 2007, 14:59
Agree with answer. E. 6 or -6 when putting both statements together. insuff.
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Re: DS - Value of y/x [#permalink]  28 Oct 2007, 21:45
johnbaker wrote:
If both x and y are nonzero numbers, what is the value of y/x ?
(1) x = 6
(2) y^2 = x^2

S1: insuff.

S2: x=1 y=1 x/y=1

x=-1 y=1 x/y=-1

Insuff.

1&2:
my initial answer was C b/c for some reason I ignored what I just did above =(.

x=6 y=6 or x=6 y=-6

So E.
Manager
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Re: DS - Value of y/x [#permalink]  28 Oct 2007, 23:43
johnbaker wrote:
If both x and y are nonzero numbers, what is the value of y/x ?
(1) x = 6
(2) y^2 = x^2

E...

statement 1 doesn't say anything about Y, so out

statement 2, we still don't know if Y is 6 or -6.....
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[#permalink]  29 Oct 2007, 00:11
St1:
Insufficient. Nothing about y.

St2:
(y+x)(y-x) = 0
If x = 1, y = 1, then the above statement is true and 1/1 = 1.
If x = -1, y = 1, then the above statement is true but 1/-1 = -1.
Insufficient.

St1 and St2:
y = 36, y = +6 or -6.

If y = 6 and x = 6, then (y+x)(y-x) = 0 and 6/6 = 1.
If y = -6 and x = 6, then (y+x)(y-x) = 0 but 6/-6 = -1.
Insufficient.

Ans E
[#permalink] 29 Oct 2007, 00:11
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# If both x and y are nonzero numbers, what is the value of

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