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If c and d are integers, is c even? a. c(d+1) is even b. [#permalink]
11 Oct 2008, 01:28
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If c and d are integers, is c even? a. c(d+1) is even b. (c+2)(d+2) is even
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Re: Even numbers DS [#permalink]
11 Oct 2008, 05:44
Ans is E.
(a) when d is odd, c can be even or odd (b) when (c+2) is even, c is even. when (d+2) is even, c can be odd or even.
both together doesn't give any info. So E.
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Re: Even numbers DS [#permalink]
12 Oct 2008, 14:28
redbeanaddict wrote: If c and d are integers, is c even? a. c(d+1) is even b. (c+2)(d+2) is even from a even*odd(d is even) or odd *even thus(d is odd) or both even ( c even d is odd) from 2 odd *even ( c is odd, d is even) or even*odd ( c is even, d is odd) or even * even thus both are even both together E
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Re: Even numbers DS [#permalink]
12 Oct 2008, 14:33
Clearly E
I will go with the explanations above
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Re: Even numbers DS [#permalink]
12 Oct 2008, 23:11
C for me.
from 1: c can be even and d can be odd / even or c and d will be odd.
From 2: c and d can be even, c can be even and d can be odd/even, c is odd and d is even.
Combining the two,
c is even and d can be odd/even. Hence, sufficient.
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Re: Even numbers DS [#permalink]
13 Oct 2008, 00:26
Redbeanaddict's answer made me rethink ... C. A) C ODD and D even -- not possible B) C ODD and D EVEN -- not possible So combining the two, C has to be even and D can be odd/even. Amazing what time pressure does to our thinking.
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Re: Even numbers DS [#permalink]
13 Oct 2008, 04:59
Answer is C I think I was  Unlike guttal07, may be I need to be under time pressure to solve the problem properly
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Re: Even numbers DS [#permalink]
13 Oct 2008, 16:14
If c and d are integers, is c even? a. c(d+1) is even b. (c+2)(d+2) is ev
1) cd+c=even, well we dont anything here c could be even.. or odd, 2) again same thing cd+2c+2d+4=even
together
cd+c=even, ok..even+c+2d=even
we know that 2d is even, even+c=even, which means C has to be even
C it is
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Re: Even numbers DS
[#permalink]
13 Oct 2008, 16:14
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