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2. If x and y are +ve integers, (2^Y)X = 176, what is the least possible value of XY?

Explanation to find out the least value of X*Y, we need to find out the maximum value of 2^Y, which will be divisible by 176. max value is 16 that means Y will 4 and X will be 16

for Q2, it says that x and y are +ve integers. this implies they cant be zero. so for the product to be minimum, we take the max possible value of y which is 4. the value of x, under this case is 11. so the ans is 44.