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If Company M ordered a total of 50 computers and printers an [#permalink]

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29 Jan 2013, 11:38

9

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

25% (medium)

Question Stats:

70% (01:56) correct
30% (00:45) wrong based on 187 sessions

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If Company M ordered a total of 50 computers and printers and Company N ordered a total of 60 computers and printers, how many printers did company M order?

(1) Company M and Company N ordered the same number of computers (2) Company N ordered 10 more printers than Company M

Re: If Company M ordered a total of 50 computers and printers an [#permalink]

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29 Jan 2013, 12:54

mjg2110 wrote:

Hi

I get stuck in this one! Why is not C the right answer??? Thanks!!

If company M ordered a total of 50 computers and printers and company N order a total of 60 computers and printers. How many computers does company M order?

1) Company M and N order the same number of computers 2) Company N order 10 computers more than M.

I found this q weird. For M, C(M) + P(M) = 50 For N, C(N)+ P(N) = 60

A does not say anything about printers for M and N. It can be 10 and 10, 20 and 20, 30 and 30 or any such combi B same issue as A On Combining, the info in both options is ambiguous. M and N computers are same where B says N has 10 more than M. How both of them can be true?
_________________

If Company M ordered a total of 50 computers and printers and Company N ordered a total of 60 computers and printers, how many printers did company M order?

(1) Company M and Company N ordered the same number of computers (2) Company N ordered 10 more printers than Company M

I get stuck in this one! Why is not C the right answer???

Thanks!!

It's straight E. Consider the following cases:

#1: M ordered 5 computers and 45 printers, N ordered 5 computers and 55 printers; #2: M ordered 10 computers and 40 printers, N ordered 10 computers and 50 printers;

Re: If Company M ordered a total of 50 computers and printers an [#permalink]

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23 Oct 2015, 08:21

This looks straight forward at first. From the question, two equations are introduced and four variables are introduced.

Then (1) and (2) each introduce what appears to be an additional equation so we have four equations and four variables.

At this point I selected answer C without solving assuming that our variable could be solved by rules of solvability with 4 equations. The problem is that the equation that (2) introduces is in fact identical to the information you already have. In essence it is not a new equation and thus you are still left with 4 variables and only 3 equations.

Does anyone have a more succinct way to explain this or identify this pattern in future problems?

This looks straight forward at first. From the question, two equations are introduced and four variables are introduced.

Then (1) and (2) each introduce what appears to be an additional equation so we have four equations and four variables.

At this point I selected answer C without solving assuming that our variable could be solved by rules of solvability with 4 equations. The problem is that the equation that (2) introduces is in fact identical to the information you already have. In essence it is not a new equation and thus you are still left with 4 variables and only 3 equations.

Does anyone have a more succinct way to explain this or identify this pattern in future problems?

The rule is that you need to have n "distinct" equations to solve to "n" variables. This is especially true for DS questions. Do not mark C or E in DS questions without actually loooking at the equations you get either from the question stem and the statements. This is the "pattern" you are talking about.

You get the same equations of \(C_m + P_m = 50\) from the question stem+2 statements combined.

Thus, be very careful in DS questions when you are given 'n' variables and 'n' equations. These equations must be distinct to give any unique value.

Re: If Company M ordered a total of 50 computers and printers an [#permalink]

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23 Oct 2015, 13:00

Engr2012 wrote:

jbburf wrote:

This looks straight forward at first. From the question, two equations are introduced and four variables are introduced.

Then (1) and (2) each introduce what appears to be an additional equation so we have four equations and four variables.

At this point I selected answer C without solving assuming that our variable could be solved by rules of solvability with 4 equations. The problem is that the equation that (2) introduces is in fact identical to the information you already have. In essence it is not a new equation and thus you are still left with 4 variables and only 3 equations.

Does anyone have a more succinct way to explain this or identify this pattern in future problems?

The rule is that you need to have n "distinct" equations to solve to "n" variables. This is especially true for DS questions. Do not mark C or E in DS questions without actually loooking at the equations you get either from the question stem and the statements. This is the "pattern" you are talking about.

You get the same equations of \(C_m + P_m = 50\) from the question stem+2 statements combined.

Thus, be very careful in DS questions when you are given 'n' variables and 'n' equations. These equations must be distinct to give any unique value.

Hope this helps.

Well said, and thank you for the response. The problem here was that an additional equation was introduced but it was not distinct.

Re: If Company M ordered a total of 50 computers and printers an [#permalink]

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21 Jan 2016, 02:02

mjg2110 wrote:

If Company M ordered a total of 50 computers and printers and Company N ordered a total of 60 computers and printers, how many printers did company M order?

(1) Company M and Company N ordered the same number of computers (2) Company N ordered 10 more printers than Company M

I get stuck in this one! Why is not C the right answer???

Thanks!!

Admins can you please edit this question take this part out "I get stuck in this one!Why is not C the right answer??? " sothat one cannot see the answer. Thanks.

Company M: a+b=50, Company N: x+y=60, b=?

(1) a=x, ok, y-b=10, not sufficient (2) y=b+10 same information as above, not sufficient (1)+(2) We have twice the same info, so still not sufficient.

Answer E
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Re: If Company M ordered a total of 50 computers and printers an [#permalink]

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23 Jun 2016, 03:36

Bunuel wrote:

mjg2110 wrote:

If Company M ordered a total of 50 computers and printers and Company N ordered a total of 60 computers and printers, how many printers did company M order?

(1) Company M and Company N ordered the same number of computers (2) Company N ordered 10 more printers than Company M

I get stuck in this one! Why is not C the right answer???

Thanks!!

It's straight E. Consider the following cases:

#1: M ordered 5 computers and 45 printers, N ordered 5 computers and 55 printers; #2: M ordered 10 computers and 40 printers, N ordered 10 computers and 50 printers;

Hey! I am also stuck with this question. The above statements that you mentioned didn't give us a unique answer on their own. But when i am combining them, i am using this approach and reaching to an answer.

Let (M computers) MC = x therefore, (M Printers) MP = 50-x .......(eq1) On other hand NC = y and NP= 60-y

Now statement 1 says : x=y ie. Company M and N ordered same number of computer. Thus NP becomes 60-x (because NP WAS "60-y" and now x=y) so now, NP= 60-x .........(eq2)

statement 2 says: NP=10MP

Now combining 1 and 2 gives us: ie (60-x) = 10(50-x)

If Company M ordered a total of 50 computers and printers and Company N ordered a total of 60 computers and printers, how many printers did company M order?

(1) Company M and Company N ordered the same number of computers (2) Company N ordered 10 more printers than Company M

I get stuck in this one! Why is not C the right answer???

Thanks!!

It's straight E. Consider the following cases:

#1: M ordered 5 computers and 45 printers, N ordered 5 computers and 55 printers; #2: M ordered 10 computers and 40 printers, N ordered 10 computers and 50 printers;

Hey! I am also stuck with this question. The above statements that you mentioned didn't give us a unique answer on their own. But when i am combining them, i am using this approach and reaching to an answer.

Let (M computers) MC = x therefore, (M Printers) MP = 50-x .......(eq1) On other hand NC = y and NP= 60-y

Now statement 1 says : x=y ie. Company M and N ordered same number of computer. Thus NP becomes 60-x (because NP WAS "60-y" and now x=y) so now, NP= 60-x .........(eq2)

statement 2 says: NP=10MP

Now combining 1 and 2 gives us: ie (60-x) = 10(50-x)

Please help

(2) says: Company N ordered 10 more printers than Company M, not 10 times as many.
_________________

Re: If Company M ordered a total of 50 computers and printers an [#permalink]

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23 Jun 2016, 09:28

Straight E (1) M and N bought same number of computer = {Both 20 computers} or {30 computers} or {40 computers} ..etc etc. Cannot find no. of printers by this information INSUFFICIENT (2) N bought 10 more printers than N= {M-30 N-40} or {M-44 N-54} or {M-1 N-11} No. of printers is again variable INSUFFICIENT

COMBINE MC & NC=25 MP=25 NP=35 [MP+MC= 50 NP+NC=60] or MC & NC=10 MP=40 NP=50 [MP+MC= 50 NP+NC=60] or MC & NC=1 MP=49 NP=59 [MP+MC= 50 NP+NC=60] or MC & NC=0 MP=50 NP=60 [MP+MC= 50 NP+NC=60]

Even afer combining the two statements number of printers that company M bought can be anything from 1 to 50

HENCE 0

DO NOT BE AFRAID TO CHOOSE E WHEN CALCULATIONS OBVIOUSLY POINTS THAT THE OPTION IS INDEED E

mjg2110 wrote:

If Company M ordered a total of 50 computers and printers and Company N ordered a total of 60 computers and printers, how many printers did company M order?

(1) Company M and Company N ordered the same number of computers (2) Company N ordered 10 more printers than Company M

I get stuck in this one! Why is not C the right answer???

Thanks!!

_________________

Posting an answer without an explanation is "GOD COMPLEX". The world doesn't need any more gods. Please explain you answers properly. FINAL GOODBYE :- 17th SEPTEMBER 2016.

Re: If Company M ordered a total of 50 computers and printers an [#permalink]

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02 Aug 2016, 01:31

mjg2110 wrote:

If Company M ordered a total of 50 computers and printers and Company N ordered a total of 60 computers and printers, how many printers did company M order?

(1) Company M and Company N ordered the same number of computers (2) Company N ordered 10 more printers than Company M

I get stuck in this one! Why is not C the right answer???

Thanks!!

From stimulus mp+mc=50 np+nc=60 (1) Company M and Company N ordered the same number of computers 2*c +mp+np=110 ------------------> because (50+60=110) INSUFFICIENT (2) Company N ordered 10 more printers than Company M mc+nc+2p=100--------------------------->because (110-10=100) INSUFFICIENT

ADDING BOTH STATEMENTS 2C+2P=210 C+P=105

CANNOT FIGURE INDIVIDUAL VALUE OF COMPUTER AND PRINTERS

INSUFFICIENT

E IS ANSWER
_________________

Posting an answer without an explanation is "GOD COMPLEX". The world doesn't need any more gods. Please explain you answers properly. FINAL GOODBYE :- 17th SEPTEMBER 2016.

gmatclubot

Re: If Company M ordered a total of 50 computers and printers an
[#permalink]
02 Aug 2016, 01:31

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