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# if |d-9| = 2d, then d = a. -9 b. -3 c. 1 d. 3 e. 9

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if |d-9| = 2d, then d = a. -9 b. -3 c. 1 d. 3 e. 9 [#permalink]  05 Mar 2007, 08:44
if |d-9| = 2d, then d =

a. -9
b. -3
c. 1
d. 3
e. 9
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Re: an absolute value [#permalink]  05 Mar 2007, 09:42
Stormgal wrote:
if |d-9| = 2d, then d =

a. -9
b. -3
c. 1
d. 3
e. 9

D.

case 1: d-9>0
d-9 = 2d
d = -9
but -9-9 <0
not solution

case 2: d-9<0
-(d-9) = 2d
d = 3
check: 3-9<0
solution
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good answer.... i'd do it a bit differently here...

first i notice that d must be positive (since |d-9| is always positive so does 2d and hence d). so eliminate A and B
now i just quicly check C,D,E... E is clearly wrong since |d-9|=0 and 1 is also not giving a true statement. 3 does the trick....
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