Author
Message
TAGS:

Hide Tags
Manager

Joined: 26 Jun 2006

Posts: 152

Followers: 1

Kudos [? ]:
3
[0 ] , given: 0

Got it! After carefully tracing back my steps I reached the same conclusion.
I actually approached this problem the same way you did, but I counted way too many 10s in 30! (Somehow 20 produced two 10s for me instead of one!)

SVP

Joined: 05 Jul 2006

Posts: 1512

Followers: 5

Kudos [? ]:
212
[0 ] , given: 39

I CANT GET IT (INTIGERS AND FACTORIALS) [#permalink ]

Show Tags
04 Sep 2006, 11:53

If d is a positive integer and f is the prodcut of the first 30 positive integers, what is the value of d?
(1) 10^d is a factor of f
(2) d > 6
Back to top

Current Student

Joined: 28 Dec 2004

Posts: 3385

Location: New York City

Schools: Wharton'11 HBS'12

Followers: 14

Kudos [? ]:
239
[0 ] , given: 2

This question is testing ur understanding of number properties...
f=30!
D is a factor of f..
(1) 10^d is a factor of F....
well..10 is a fator of F, so is 100...Insuff
think of it this way...what are the prime factors of 10?
10=2*5, then 10^d, will have prime factors=2^a * 5^b..
now..we know that there are going to be fewer 5s in 30 factorial...so whatever the power of 5 is...will determine the power of 10^d.
in other words 5^b=10^d (the biggest possible value of 10 tht is a factor of 30!)
(2) d is greater than 6...
well that by itself is insuff
together Sufficient...
here is how..
30/5=6 fives...
25 has 2 fives, so there is one additional 5...
so we know that 5^b; where b=7...
so ..10^7 is the highest possible factor of 10 in 30!...
Sufficient...

SVP

Joined: 05 Jul 2006

Posts: 1512

Followers: 5

Kudos [? ]:
212
[0 ] , given: 39

Thanks a lot ... i appreciate the time you gave me

to write this detailed explanation

Manager

Joined: 04 May 2006

Posts: 173

Location: paris

Followers: 1

Kudos [? ]:
20
[0 ] , given: 0

DS- Number properties [#permalink ]

Show Tags
26 Nov 2006, 13:02

If d is a positive integer and f is the product of the first 30 positive integers, what's the value of d?

1. 10^d is a factor of f

2. d>6

I did this Q right, however when I checked the factorial of "f" in Excel I got a different result... is Bill gates wrong

_________________

time is not on my side

Last edited by

ugo_castelo on 27 Nov 2006, 04:26, edited 1 time in total.

VP

Joined: 15 Jul 2004

Posts: 1473

Schools: Wharton (R2 - submitted); HBS (R2 - submitted); IIMA (admitted for 1 year PGPX)

Followers: 21

Kudos [? ]:
146
[0 ] , given: 13

Re: DS- Number properties [#permalink ]

Show Tags
27 Nov 2006, 01:23

ugo_castelo wrote:

If d is a positive integer and f is the product of the first 30 integers, what's the value of d?

1. 10^d is a factor of f

2. d>6

I did this Q right, however when I checked the factorial of "f" in Excel I got a different result... is Bill gates wrong

What does first 30 integers mean? What is the FIRST Integer anyway?

Manager

Joined: 04 May 2006

Posts: 173

Location: paris

Followers: 1

Kudos [? ]:
20
[0 ] , given: 0

yes, it's Positive... integers ( typed too fast)

_________________

time is not on my side

Senior Manager

Joined: 01 Sep 2006

Posts: 301

Location: Phoenix, AZ, USA

Followers: 1

Kudos [? ]:
19
[0 ] , given: 0

Re: DS- Number properties [#permalink ]

Show Tags
27 Nov 2006, 09:58

If d is a positive integer and f is the product of the first 30 positive integers, what's the value of d?
1. 10^d is a factor of f
2. d>6
1st 30 = 1*2*3*4*... *30
we know this has 5*10*15*20*30 so 10^1 is fcator 10^2 is factor
(1) 10^d is factor insuff
(2) insuff on its own
Togather
Lets check how many multiple 5s are in product
5*10*15*20*25*30
5*5*2*5*3*5*4*5*5*5*6 so 5^7
we also have many 2s 2,4,8,... surely we can find 7 or more
5^7*2*7=10^7
Answer C

Manager

Joined: 04 May 2006

Posts: 173

Location: paris

Followers: 1

Kudos [? ]:
20
[0 ] , given: 0

that's correct

the same way I did

However , when I checked the Factorial of 30 in excel, I got more then 10^7

that's why the surprise

_________________

time is not on my side

Manager

Joined: 03 Jul 2005

Posts: 192

Location: City

Followers: 1

Kudos [? ]:
8
[0 ] , given: 0

GMATPREP: Postive Integer [#permalink ]

Show Tags
01 Jan 2007, 02:36

If d is a positive integer and f is the product of the first 30 positive integers, what is the value of d?
1) 10^d is a factor of f
2) d > 6
What is the best way of handling this type of question
OA to follow

SVP

Joined: 01 May 2006

Posts: 1798

Followers: 9

Kudos [? ]:
132
[0 ] , given: 0

(C) for me

f = 30!

To me, I decompose 10 in prime factor.

10 = 5*2.

Obviously, in 30!, there is a lot of "2" prime factors. So, the limit comes from the number of 5 prime factors.

5 is contained in : 5, 10, 15, 20, 25, 30.

So, we have 6 5 prime factors available.

From 1
f = k*10^d

Following what we said about 5, d could be anything from 1 to 6.

INSUFF.

From 2
d > 6 : d = 7 or d = 8. It gives nothing alone.

INSUFF.

Both (1) and (2)
We know the maximum is 6... Is it a typo? I would say d >= 6. Because d cannot be 7.

But we can conclude impossible

SUFF.

Manager

Joined: 03 Jul 2005

Posts: 192

Location: City

Followers: 1

Kudos [? ]:
8
[0 ] , given: 0

OA is ......
C
The question for 2 is d > 6, no typo

Last edited by

lfox2 on 01 Jan 2007, 04:09, edited 1 time in total.

SVP

Joined: 01 May 2006

Posts: 1798

Followers: 9

Kudos [? ]:
132
[0 ] , given: 0

Fig wrote:

(C) for me

f = 30!

To me, I decompose 10 in prime factor.

10 = 5*2.

Obviously, in 30!, there is a lot of "2" prime factors. So, the limit comes from the number of 5 prime factors.

5 is contained in : 5, 10, 15, 20, 25, 30.

So, we have 6 5 prime factors available.

From 1 f = k*10^d

Following what we said about 5, d could be anything from 1 to 6.

INSUFF.

From 2 d > 6 : d = 7 or d = 8. It gives nothing alone.

INSUFF.

Both (1) and (2) We know the maximum is 6... Is it a typo? I would say d >= 6. Because d cannot be 7.

But we can conclude impossible

SUFF.

No typo :p... I have forgotten 25 = 5*5

... 7 5 are available

Intern

Joined: 10 Apr 2006

Posts: 33

Followers: 0

Kudos [? ]:
10
[0 ] , given: 0

c for me as well.
10 has 2 and 5 as factors,
2 occurs
30 / 2 = 15;
15/2 = 7;
7/2 = 3
3/2 = 1;
(15 + 7 + 3 + 1) = 26 times
While 5 occurs,
30/ 5 = 6
6/5 = 1
6 + 1 = 7 times
there for 10 will have 7 instances in 30!

Intern

Joined: 08 May 2006

Posts: 24

Followers: 0

Kudos [? ]:
1
[0 ] , given: 0

GMATPREP DS [#permalink ]

Show Tags
25 Apr 2007, 06:00

If d is a positive integer and f is the product of the first 30 positive integers what is the value of d?
(1) 10^d is a factor of f.
(2) d>6
Can someone suggest a good technique for this one please!

VP

Joined: 08 Jun 2005

Posts: 1146

Followers: 6

Kudos [? ]:
164
[0 ] , given: 0

Re: GMATPREP DS [#permalink ]

Show Tags
25 Apr 2007, 12:31

doc14 wrote:

If d is a positive integer and f is the product of the first 30 positive integers what is the value of d? (1) 10^d is a factor of f. (2) d>6 Can someone suggest a good technique for this one please!

The best way to solve problems like that is to brake it into small pieces:

f = 1*2*3*4*5*6*7*8*9*10*11*12*13*14*15*16*17*18*19*20*

21*22*23*24*25*26*27*28*29*30

First off - try to convert the number above into something that you can work with - look at the statements first to get more info.

I left only the numbers that are multiplication of 10 !

2*4*5*10*20*15*25*30 = convert into = 2*2*5*10*2*10*3*5*5*5*10*3

get rid off the 3 = 10*10*10*10*10*10*10 (total of 7)

now the magic begins !

statement 1
we were asked about 10^n as a factor of - f - so look up - there no way to know - d can be 1,2,3,4,5,6,7

insufficient
statement 2
dosen't say much by itself

insufficient
statment 2&1
since there is 7 exponents of 10 that are a factor of - f

if n>6 n has to be 7.

sufficient

Current Student

Joined: 22 Apr 2007

Posts: 1097

Followers: 5

Kudos [? ]:
25
[0 ] , given: 0

I think the best way to solve the problem is this:
10 can only be made up of 2s and 5s (2x5). In the list of 1x2x3...x30, there are plenty of 2s, but only 7 5s (5, 10, 15, 20, 30 have one each, and 25 has 2 5s). So, f has 7 10s .. ie, f = k x 10^7
So, from statement one, d can be anything from 1 to 7
From statement two, d should be >6
Neither of the statements are sufficient in themselves, but together, they make d = 7
Hence C

GMAT Club Legend

Joined: 07 Jul 2004

Posts: 5062

Location: Singapore

Followers: 29

Kudos [? ]:
282
[0 ] , given: 0

f = 30!
St1:
10^d is a factor of f. d can be 1,2,3 etc... Insufficient.
St2:
Uesless. We know nothing much else. Insufficient.
St1 and St2:
If d = 7, then we have 10^7 = (2^7)*(5^7). That's all the 5's we have in 30!. So d cannot be 8 and up. Sufficient.
Ans C

Intern

Joined: 08 May 2006

Posts: 24

Followers: 0

Kudos [? ]:
1
[0 ] , given: 0

OA is C .
Thanks for all the replies!

Director

Joined: 09 Aug 2006

Posts: 763

Followers: 1

Kudos [? ]:
147
[0 ] , given: 0

Re: DS : product of first 30 positive integers [#permalink ]

Show Tags
10 Aug 2007, 01:23

trahul4 wrote:

If d is a positive integer and f is the product if the first 30 positive integers, what is the value of d? 1. 10^d is a factor of f. 2. d>6

I get C as well.

Stat1: d =1 or 2; insuff

Stat2: insuff

Stat 1&2: d=7, suff.

If 10^d is a factor of 30! and d>6 then d has to be 7 since 10^d is not a factor of 30! if d>7.

Re: DS : product of first 30 positive integers
[#permalink ]
10 Aug 2007, 01:23

Go to page
Previous
1 2 3 4
Next
[ 70 posts ]

Similar topics
Author
Replies
Last post
Similar Topics:

1
A, B, C, D, E, and F are six consecutive positive odd integers in
stonecold
2
25 Apr 2016, 15:10

3
If d is a positive integer, is d^1/2 an integer?
Bunuel
5
26 Feb 2014, 02:26

2
If c and d are positive, is d an integer ?
pathakshashi
3
22 Jul 2012, 18:17

75
If d is a positive integer and f is the product of the first
enigma123
21
28 Jan 2012, 18:13

6
If d is a positive integer, is d^1/2 an integer ?
Bunuel
7
15 Feb 2011, 11:53