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Re: Is it a hard question [#permalink]
26 Nov 2010, 10:18

Expert's post

chiragatara wrote:

If each of a, b and c is positive, and a = 5b + 7c, what is the value of a/b?

1) 2b + 5c = 50 2) 3b - 5c = c

Given: \(a=5b+7c\).

Now, as we are asked to get the value of \(\frac{a}{b}\) then divide both parts of \(a=5b+7c\) by \(b\) (to have LHS equal to \(\frac{a}{b}\)): \(\frac{a}{b}=5+7\frac{c}{b}\). So, basically finding the value of \(\frac{c}{b}\) will be sufficient.

(1) 2b + 5c = 50 --> we can neither solve for unknowns (2 distinct linear equations, 3 variables) nor get the desired ratio. Not sufficient. (2) 3b - 5c = c --> \(3b=6c\) --> \(\frac{c}{b}=\frac{1}{2}\). Sufficient.

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