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If each term in the sum A1 + A2 + .....+ An is either 7 or

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Director
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If each term in the sum A1 + A2 + .....+ An is either 7 or [#permalink]

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New post 15 Dec 2007, 20:26
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If each term in the sum A1 + A2 + .....+ An is either 7 or 77 and the sum equals 350
,which of the following could be equal to n ?

A 38
B 39
C 40
D 41
E 42
CEO
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Re: PS - GmatPrep [#permalink]

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New post 15 Dec 2007, 21:58
ashkrs wrote:
If each term in the sum A1 + A2 + .....+ An is either 7 or 77 and the sum equals 350
,which of the following could be equal to n ?

A 38
B 39
C 40
D 41
E 42


I get C.

Took me about 1min 30 sec, but it seems to work...

Just tried values 7*38=266 +77=343 +7

So 39*7 +77=350.

Unless Im missin somethin.
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Re: PS - GmatPrep [#permalink]

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New post 15 Dec 2007, 22:06
GMATBLACKBELT wrote:
ashkrs wrote:
If each term in the sum A1 + A2 + .....+ An is either 7 or 77 and the sum equals 350
,which of the following could be equal to n ?

A 38
B 39
C 40
D 41
E 42


I get C.

Took me about 1min 30 sec, but it seems to work...

Just tried values 7*38=266 +77=343 +7

So 39*7 +77=350.

Unless Im missin somethin.


no u are not missin anythin....OA is C.
but how did you arrived..on 7*38=266 +77=343 +7

i tried plugging too ..but tool hell lotta time for me to put all combinations ..before i arrived at c ..just wanted to know whats the best way to do this..
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New post 16 Dec 2007, 02:32
Expert's post
C.

other way.

350/7=50 but 50 is out of answer cases.

we add one 77 and exclude eleven 7, so 350=(50-11)*7+1*77 ==> n=50-11+1=40
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New post 17 Dec 2007, 00:26
walker wrote:
C.

other way.

350/7=50 but 50 is out of answer cases.

we add one 77 and exclude eleven 7, so 350=(50-11)*7+1*77 ==> n=50-11+1=40
Sorry I didn't understand how you came up with the above equation? Plz elaborate
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 [#permalink]

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New post 17 Dec 2007, 00:40
Expert's post
lonesome307 wrote:
Sorry I didn't understand how you came up with the above equation? Plz elaborate


step 1. we can represent 350 as a sum of only 7. 350=50*7. So, we should sum 50 terms - out of answers.

step 2. we add one 77 and exclude eleven 7 to balance the sum: 350=50*7+1*77-11*7=50*39+1*77. we have 40 terms.

we had gone to the next step if 40 would not be answer.

possible step: add next 77 and exclude eleven 7 to balance question:
350=50*7+2*77-22*7=50*28+2*77. we have 30 terms.
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New post 17 Dec 2007, 01:35
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Late, but C:

350 = 7*50 (but we don't have such answer)
350-77 = 273 (and 273/7 = 39), so answer is 40.

walker, nice trick - noted!
  [#permalink] 17 Dec 2007, 01:35
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