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Using the quadratic equation (-b +/-\sqrt{b2-4ac}/2a we find the roots as follows

-(-4)+/-\sqrt{4^2 - 4(1)(-65)}/2(1) So the first root is 4+\sqrt{16+260}/2 = 4+\sqrt{276}/2= 4+2\sqrt{69}/2 The second root is 4-\sqrt{16+260}/2 = 4-\sqrt{276}/2= 4-2\sqrt{69}/2

The sum of the roots is 4+2\sqrt{69}/2 + 4-2\sqrt{69}/2 = 8/2= 4 The answer should be 4
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Re: If f(x)=5x^2 and g(x)=x^2 + 12x + 85, what is the sum of all [#permalink]
10 Jan 2014, 13:57

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