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Re: What is the value of (-1)^{g^4 + g - 1} ? 1. g is an [#permalink]
Bunuel wrote:
ugimba wrote:
What is the value of \((-1)^{g^4 + g - 1}\) ?

1. \(g\) is an integer
2. \(g\) is even


Source: GMAT Club Tests - hardest GMAT questions

shouldn't we consider negative values for option 1? ( 'g' is integer)? in this case, then A wont fit right?


BELOW IS REVISED VERSION OF THIS QUESTION:
If \(g\) is an integer what is the value of \((-1)^{g^4 - 1}\) ?

(1) \(g^2<{1}\)
(2) \(g^2+2 g=0\)

SOLUTION:
(1) \(g^2<{1}\) --> since \(g\) is an integer then \(g=0\). Sufficient to calculate the value of \((-1)^{g^4 - 1}\).

(2) \(g^2+2g=0\) --> \(g(g+2)=0\) --> \(g=0\) or \(g=-2\). Since both possible values of \(g\) are even then \((-1)^{even^4 - 1}=(-1)^{even-1}=(-1)^{odd}=-1\). Sufficient.

Answer: D.



Superb question, since g^2<1 g cannot have any value except zero had it been g<1 than the answer would have been B

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Re: What is the value of (-1)^{g^4 + g - 1} ? 1. g is an [#permalink]
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