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# If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =?

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Manager
Joined: 16 Jan 2011
Posts: 103
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If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =? [#permalink]

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19 Aug 2013, 11:38
1
KUDOS
1
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Difficulty:

25% (medium)

Question Stats:

72% (02:26) correct 28% (01:44) wrong based on 167 sessions

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If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =?

(A) – 10
(B) – 8
(C) – 6
(D) 0
(E) 4
[Reveal] Spoiler: OA

Last edited by Bunuel on 19 Aug 2013, 11:52, edited 1 time in total.
Edited the question and added the OA
Director
Joined: 14 Dec 2012
Posts: 842
Location: India
Concentration: General Management, Operations
GMAT 1: 700 Q50 V34
GPA: 3.6
Followers: 51

Kudos [?]: 1044 [0], given: 197

Re: If g(x) = ax5 + bx3 + 1 [#permalink]

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19 Aug 2013, 11:51
Galiya wrote:
If g(x) = ax5 + bx3 + 1, and g(5) = 10, then g(–5) =?

(A) – 10
(B) – 8
(C) – 6
(D) 0
(E) 4

given:
$$g(5) = 10$$
therefore
$$a*5^5 + b5^3 + 1 = 10$$
$$a*5^5 + b5^3 = 9$$ ..................................(1
$$g(-5) = -a*5^5 - b5^3 + 1$$
$$=- (a*5^5 + b5^3)+1$$
now using 1
$$g(-5) = -9 + 1 = -8$$

hence B
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Senior Manager
Joined: 10 Jul 2013
Posts: 335
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Kudos [?]: 257 [0], given: 102

Re: If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =? [#permalink]

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19 Aug 2013, 13:39
Galiya wrote:
If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =?

(A) – 10
(B) – 8
(C) – 6
(D) 0
(E) 4

g(5) = 10
or, 5^5 a + 5^3 b + 1 = 10
or, 5^5 a + 5^3 b = 9

g(-5) = -5^5 a - 5^3 b + 1 = - (5^5 a + 5^3 b) + 1 = - 9 + 1 = - 8 = (B)
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Re: If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =? [#permalink]

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13 Sep 2014, 22:45
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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =?   [#permalink] 13 Sep 2014, 22:45
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