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# If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =?

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If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =? [#permalink]  19 Aug 2013, 10:38
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If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =?

(A) – 10
(B) – 8
(C) – 6
(D) 0
(E) 4
[Reveal] Spoiler: OA

Last edited by Bunuel on 19 Aug 2013, 10:52, edited 1 time in total.
Edited the question and added the OA
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Joined: 14 Dec 2012
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Concentration: General Management, Operations
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Kudos [?]: 730 [0], given: 197

Re: If g(x) = ax5 + bx3 + 1 [#permalink]  19 Aug 2013, 10:51
Galiya wrote:
If g(x) = ax5 + bx3 + 1, and g(5) = 10, then g(–5) =?

(A) – 10
(B) – 8
(C) – 6
(D) 0
(E) 4

given:
$g(5) = 10$
therefore
$a*5^5 + b5^3 + 1 = 10$
$a*5^5 + b5^3 = 9$ ..................................(1
$g(-5) = -a*5^5 - b5^3 + 1$
$=- (a*5^5 + b5^3)+1$
now using 1
$g(-5) = -9 + 1 = -8$

hence B
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Senior Manager
Joined: 10 Jul 2013
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Re: If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =? [#permalink]  19 Aug 2013, 12:39
Galiya wrote:
If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =?

(A) – 10
(B) – 8
(C) – 6
(D) 0
(E) 4

g(5) = 10
or, 5^5 a + 5^3 b + 1 = 10
or, 5^5 a + 5^3 b = 9

g(-5) = -5^5 a - 5^3 b + 1 = - (5^5 a + 5^3 b) + 1 = - 9 + 1 = - 8 = (B)
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Re: If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =? [#permalink]  13 Sep 2014, 21:45
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Re: If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =?   [#permalink] 13 Sep 2014, 21:45
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