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If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =?

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Manager
Manager
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Joined: 15 Jan 2011
Posts: 108
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Kudos [?]: 26 [0], given: 13

If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =? [#permalink] New post 19 Aug 2013, 10:38
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Difficulty:

  25% (medium)

Question Stats:

75% (01:00) correct 25% (01:29) wrong based on 61 sessions
If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =?

(A) – 10
(B) – 8
(C) – 6
(D) 0
(E) 4
[Reveal] Spoiler: OA

Last edited by Bunuel on 19 Aug 2013, 10:52, edited 1 time in total.
Edited the question and added the OA
Director
Director
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Joined: 14 Dec 2012
Posts: 837
Location: India
Concentration: Finance, Real Estate
GMAT 1: 640 Q49 V29
GMAT 2: 670 Q50 V29
GMAT 3: 620 Q49 V26
GMAT 4: 700 Q50 V34
GPA: 3.6
Followers: 37

Kudos [?]: 538 [0], given: 197

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Re: If g(x) = ax5 + bx3 + 1 [#permalink] New post 19 Aug 2013, 10:51
Galiya wrote:
If g(x) = ax5 + bx3 + 1, and g(5) = 10, then g(–5) =?



(A) – 10
(B) – 8
(C) – 6
(D) 0
(E) 4


given:
g(5) = 10
therefore
a*5^5 + b5^3 + 1 = 10
a*5^5 + b5^3 = 9 ..................................(1
g(-5) = -a*5^5 - b5^3 + 1
=- (a*5^5 + b5^3)+1
now using 1
g(-5) = -9 + 1 = -8

hence B
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Senior Manager
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Kudos [?]: 94 [0], given: 102

Re: If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =? [#permalink] New post 19 Aug 2013, 12:39
Galiya wrote:
If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =?

(A) – 10
(B) – 8
(C) – 6
(D) 0
(E) 4


g(5) = 10
or, 5^5 a + 5^3 b + 1 = 10
or, 5^5 a + 5^3 b = 9

g(-5) = -5^5 a - 5^3 b + 1 = - (5^5 a + 5^3 b) + 1 = - 9 + 1 = - 8 = (B)
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Re: If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =?   [#permalink] 19 Aug 2013, 12:39
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If g(x) = ax^5 + bx^3 + 1, and g(5) = 10, then g(–5) =?

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