apoorvpan wrote:

what if i and j are negative.

Its mentioned that i and j are integers but its not mentioned that i and j are positive integers.

what if i = j = -3 then i+j = -6 which is not even integer.

it should be 6 to be even integer ie i = j = 3

Please clarify where am i wrong

Negative integers can also be even or dd, for example -6 is an even integer. An even number is an

integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and since -6/2=-3=integer then -6 is an even integer.

If i and j are integers, is i + j an even integer?(1) i < 10 --> no info about j. Not sufficient.

(2) i = j -->

i+j=j+j=2j, as

j is an integer then

2j is an even number. Sufficient.

Answer: B.

As for zero:The same way as above: an even number is an

integer that is "evenly divisible" by 2, i.e., divisible by 2 without a remainder and as zero is evenly divisible by 2 then it must be even (in fact zero is divisible by every integer except zero itself).

Or in another way: an even number is an

integer of the form

n=2k, where

k is an integer. So for

k=0 -->

n=2*0=0.

Also note that if we were not told that

i and

j are integers then this statement would not be sufficient as in this case

j could be for example 1.5, so

i+j=j+j=2j=3=odd or

j could be for example 1.1, so

i+j=j+j=2j=2.2\neq{integer}.

For more on Number Properties check:

math-number-theory-88376.htmlHope it helps.

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