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If, in a baseball game, a single picher can decide to throw either

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mejia401
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If, in a baseball game, a single picher can decide to throw either [#permalink] New post   Updated on: 11 Aug 2015, 15:25
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If, in a baseball game, a single picher can decide to throw either a 100mph fastball or 60mph knuckle ball on any pitch, how much less time, in seconds, does the batter have from when the ball is released as a fastball than when the ball is released as a knuckle ball? (Assume where the batter's point of contact is exactly 60ft away from the pitcher's release point. 5280ft = 1 mile.)

A. \(\frac{6}{22}s\)

B. \(\frac{7}{22}s\)

C. \(\frac{8}{22}s\)

D. \(\frac{9}{22}s\)

E. \(\frac{15}{22}s\)
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A

Originally posted by mejia401 on 10 Aug 2015, 04:13.
Last edited by mejia401 on 11 Aug 2015, 15:25, edited 2 times in total.
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Re: If, in a baseball game, a single picher can decide to throw either [#permalink] New post   10 Aug 2015, 07:36
mejia401 wrote:
If, in a baseball game, a single picher can decide to throw either a 100mph (miles per hour) fastball or 60mph knuckle ball on any pitch, how much less time, in seconds, does the batter have from when the ball is released as a fastball than when the ball is released as a knuckle ball? (Assume where the batter's point of contact is exactly 60ft away from the pitcher's release point.)

A. \(\frac{6}{22}s\)

B. \(\frac{7}{22}s\)

C. \(\frac{8}{22}s\)

D. \(\frac{9}{22}s\)

E. \(\frac{15}{22}s\)


One conversion to know is = 1 mile = 5280ft

Time taken for fastball = (60 / (100 * 5280)) * 60 * 60 = 9/22

Time taken for knuckle ball = (60 / (60 * 5280)) * 60 * 60 = 15/22

Qn is the difference btw the time taken by the two balls => 15/22 - 9/22 = 6/22

Option A
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Re: If, in a baseball game, a single picher can decide to throw either [#permalink] New post   11 Aug 2015, 00:14
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mejia401 wrote:
If, in a baseball game, a single picher can decide to throw either a 100mph (miles per hour) fastball or 60mph knuckle ball on any pitch, how much less time, in seconds, does the batter have from when the ball is released as a fastball than when the ball is released as a knuckle ball? (Assume where the batter's point of contact is exactly 60ft away from the pitcher's release point.)

A. \(\frac{6}{22}s\)

B. \(\frac{7}{22}s\)

C. \(\frac{8}{22}s\)

D. \(\frac{9}{22}s\)

E. \(\frac{15}{22}s\)


Note that for the question to be GMAT relevant, the conversion units need to be given in the question.

Time = Distance/Speed

Difference in Time = Distance/Speed1 - Distance/Speed2

Difference in Time in seconds = (60/5280) * (1/60 - 1/100) * 60*60 = 60*40*60*60/5280*60*100 = 3/11 secs

Answer (A)
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Re: If, in a baseball game, a single picher can decide to throw either [#permalink] New post   11 Aug 2015, 00:34
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Can you please check the answer , as per me and everyone aboveit should be A i.e. 6/22 seconds

Thanks,
Gaurav
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Re: If, in a baseball game, a single picher can decide to throw either [#permalink] New post   11 Aug 2015, 15:24
GauravSolanky wrote:
Can you please check the answer , as per me and everyone aboveit should be A i.e. 6/22 seconds

Thanks,
Gaurav


Thanks Gaurav. Indeed the answer wasn't posted correctly.
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Re: If, in a baseball game, a single picher can decide to throw either [#permalink] New post   19 Sep 2016, 03:19
mejia401 wrote:
If, in a baseball game, a single picher can decide to throw either a 100mph fastball or 60mph knuckle ball on any pitch, how much less time, in seconds, does the batter have from when the ball is released as a fastball than when the ball is released as a knuckle ball? (Assume where the batter's point of contact is exactly 60ft away from the pitcher's release point. 5280ft = 1 mile.)

A. \(\frac{6}{22}s\)

B. \(\frac{7}{22}s\)

C. \(\frac{8}{22}s\)

D. \(\frac{9}{22}s\)

E. \(\frac{15}{22}s\)

\(Time = \frac{Distance}{Speed}\)

And
Slower Speed = More Time
Faster Speed = Less Time

Conversions => 1 Mile = 5280ft; 1 Hour = 3600s

Therefore,

Difference in Times = \(\frac{(60*3600)}{(5280*60)} - \frac{(60*3600)}{(5280*100)} = \frac{360}{528} - \frac{(6*36)}{528} = \frac{36*(10-6)}{528} = \frac{36*4}{24*22} = \frac{6}{22}\) (A)
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Re: If, in a baseball game, a single picher can decide to throw either [#permalink]
19 Sep 2016, 03:19
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