C

This is a good problem to plug in some numbers.

There are 12 cars...1 that is twice the average of the other 11.

Lets pick $100 as the average price for each of those other 11 for a total of $1100. Now car #12 costs twice the average of the others, so it's $200. Now we add it all together 1100 + 200 = $1300 for all 12 cars. The fraction will be Car#12 / Total price of all cars.

\(\frac{$200}{$1300} = \frac{2}{13}\)

I may be missing something.

Zaur wrote:

If in a certain shipment of new cars, the cost of car X is twice the average of the other 11 cars in the shipment, what fraction of the total cost of 12 cars is the cost of car X?

a)1/12

b)1/11

c)2/13

d)2/11

e)1/6

sure it is easy, but, please, help

thanks

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J Allen Morris

**I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.

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