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If integers x, y and z are greater than 1 what is the value

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If integers x, y and z are greater than 1 what is the value [#permalink] New post 22 Oct 2008, 10:54
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If integers x, y and z are greater than 1 what is the value of x + y + z ?

(1) xyz = 70
(2) x/yz = 7/10

[Reveal] Spoiler:
I got this right. but with 2nd statement. I went to only 10x = 7yz
is that the end of 2nd statement or we can drive something with that?
[Reveal] Spoiler: OA
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Re: prep: x+y+z [#permalink] New post 22 Oct 2008, 10:58
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rishi2377 wrote:
If integers x, y and z are greater than 1 what is the value of x + y + z ?

A. xyz = 70
B. x/yz = 7/10

I got this right. but with 2nd statement. I went to only 10x = 7yz
is that the end of 2nd statement or we can drive something with that?


x,y,z >1

(1) xyz = 70 = 2*5*7 so we can find x+y+z

(2) \frac{x}{yz} = \frac{7}{10}

this just means x is a multiple of 7 and the product yz is a multiple of 10. We have no info to determine values of x,y and z.

A
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Re: prep: x+y+z [#permalink] New post 22 Oct 2008, 11:27
yup amit. OA is A...I was just curious how statement 2 shapes up.
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Re: prep: x+y+z [#permalink] New post 22 Oct 2008, 11:28
rishi2377 wrote:
If integers x, y and z are greater than 1 what is the value of x + y + z ?

A. xyz = 70
B. x/yz = 7/10

I got this right. but with 2nd statement. I went to only 10x = 7yz
is that the end of 2nd statement or we can drive something with that?



Thats where I stopped as well and figure that (7,2,5) and (14,2,10) satisfy the equation. B insuff

A is (2,5,7). good
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Re: prep: x+y+z [#permalink] New post 22 Oct 2008, 13:11
rishi2377 wrote:
If integers x, y and z are greater than 1 what is the value of x + y + z ?

A. xyz = 70
B. x/yz = 7/10

I got this right. but with 2nd statement. I went to only 10x = 7yz
is that the end of 2nd statement or we can drive something with that?


A

1. x+y+z = 14 - Sufficient
2. To many combinations - Not Sufficient
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Re: prep: x+y+z [#permalink] New post 22 Oct 2008, 23:25
rishi2377 wrote:
If integers x, y and z are greater than 1 what is the value of x + y + z ?

A. xyz = 70
B. x/yz = 7/10

I got this right. but with 2nd statement. I went to only 10x = 7yz
is that the end of 2nd statement or we can drive something with that?


This step may not be required.

x/yz = 7/2*5 = 14/4*5 = 14/2*10 = 28/4*10....and so on and hence there could be many values for x, y and z.
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Re: prep: x+y+z [#permalink] New post 23 Oct 2008, 00:17
[quote="rishi2377"]If integers x, y and z are greater than 1 what is the value of x + y + z ?

A. xyz = 70
B. x/yz = 7/10

the second statment provide a proportion as such it give endless combinations.
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Re: prep: x+y+z [#permalink] New post 05 Jan 2011, 07:29
xyz = 70
so the values could be 1 7 10
x+y+z = 18
if the values are 2 5 7
x+y+z =14
so a not sufficient
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Re: prep: x+y+z [#permalink] New post 05 Jan 2011, 07:40
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Re: prep: x+y+z [#permalink] New post 01 Mar 2011, 14:45
Bunuel, if the question states that x, y and z are greater then 1... then is ok to say that one of thoes is 1? as I read it , none of them can be one " GREATER THEN 1"???
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Re: prep: x+y+z [#permalink] New post 01 Mar 2011, 15:04
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marijose wrote:
Bunuel, if the question states that x, y and z are greater then 1... then is ok to say that one of thoes is 1? as I read it , none of them can be one " GREATER THEN 1"???


Again: "If x, y and z are integers greater than 1 ..." So none of them is one.
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Re: prep: x+y+z [#permalink] New post 01 Mar 2011, 21:03
Agree A. Prime factors. B could be multiples of prime factors (for instance all times 2)
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Re: prep: x+y+z [#permalink] New post 01 Mar 2011, 22:46
I was thinking that statement 1 is not sufficient until i factorized 70 in prime factors. So A it is.
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Re: If integers x, y and z are greater than 1 what is the value [#permalink] New post 20 Oct 2013, 10:48
Bunuel,

The problem doesnt specifically state that the integers are unique or different. Is it possible for A to be insufficient as xyz to be 7*7*5 with a sum of 19 or the answer provided above with 2*5*7 and a sum of 14?

I'm assuming the variables need to be unique integer values, but this threw me off at first.
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Re: If integers x, y and z are greater than 1 what is the value [#permalink] New post 20 Oct 2013, 10:51
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affalcon12 wrote:
Bunuel,

The problem doesnt specifically state that the integers are unique or different. Is it possible for A to be insufficient as xyz to be 7*7*5 with a sum of 19 or the answer provided above with 2*5*7 and a sum of 14?

I'm assuming the variables need to be unique integer values, but this threw me off at first.


Notice that 7*7*5 = 245 not 70.
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Re: If integers x, y and z are greater than 1 what is the value [#permalink] New post 20 Oct 2013, 10:55
Bunuel,
Yes, good correction. Obviously. For some reason I was thinking 7+7 = 14 and 14*5 = 70. Dumb mistake by me. Thank you!
Re: If integers x, y and z are greater than 1 what is the value   [#permalink] 20 Oct 2013, 10:55
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