enigma123 wrote:

If it took Carol 1/2 hour to cycle from his house to the library yesterday, was the distance that he cycled greater than 6 miles? (1mile = 5,280feet)

(1) The average speed at which Carlos cycled from his house to the library yesterday was greater than 16 feet per second.

(2) The average speed at which Carlos cycled from his house to the library yesterday was less than 18 feet per second

Guys - again the OA was not provided but I have gone for C. Can someone please let me whether I am right or wrong?

Responding to a pm:

Given: Carol traveled for 1/2 an hour i.e. 30 mins i.e. 1800 sec

Question: Was the distance he cycled greater than 6 miles or rephrase it in terms of speed: Was his speed greater than (5280*6)/1800 feet/sec = 17.6 feet/sec?

We rephrase the question in terms of speed because both the statements give info in terms of speed. If would require more calculations to work on both the statements separately. It is easier to manipulate the question and put it in terms of speed. How do we get the figure of 17.6? We find the speed at which he covers exactly 6 miles in 1/2 an hour. We get this as 17.6 feet/sec (we convert it all to feet and second because the statements give the speeds in these units). Since the question is whether he covered more than 6 miles, we just have to figure whether his speed was more than 17.6 feet/sec. In case his speed was more than 17.6 feet/sec, he would have covered more than 6 miles.

(1) The average speed at which Carlos cycled from his house to the library yesterday was greater than 16 feet per second.

His speed could have been 16.5 feet/sec or 17.8 feet/sec etc. We do not know whether his speed was greater than 17.6 feet/sec.

(2) The average speed at which Carlos cycled from his house to the library yesterday was less than 18 feet per second

His speed could have been 16.5 feet/sec or 17.8 feet/sec etc. We do not know whether his speed was greater than 17.6 feet/sec.

Same is true even when we have both the statements.

Answer E

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