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if j -2 is divisible by 4, we can say that j is 4x +2

if k-5 is divisible by 4, it means so will be k-1. and therefore k can be expressed as 4y +1

j - k will be 4x +2- (4y+1) = 4x-4y +2-1 = 4(x-y) +1

The number will have to be a multiple of 4 added to 1. 42 cant be expressed like that . Rest all options can be - (4*8+1, 4*5+1, 4*3+1, 4*1+1) Hence A.

Logical way to solve the problem j-2 = 4a ==> j=4a+2 k-5 = 4b ==> k=4b+5 j-k = 4(a-b) - 3 As the remainder can not be negative we must add divisor to the remainder to make remainder positive j-k = 4(a-b) + (4-3) j-k = 4(a-b) +1 i.e. when (j-k) is divided by 4, it will a remainder of 1 All except option "43" leave remainder 1 Solution A _________________

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Re: If j and k are positive integers, j - 2 is divisible by 4 [#permalink]
03 Feb 2014, 02:13

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