Find all School-related info fast with the new School-Specific MBA Forum

It is currently 21 Aug 2014, 04:42

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

If j and k are positive integers, j 2 is divisible by 4

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Manager
Manager
avatar
Joined: 18 Aug 2005
Posts: 86
Location: Italy, Rome caput mundi
Followers: 1

Kudos [?]: 2 [0], given: 0

If j and k are positive integers, j 2 is divisible by 4 [#permalink] New post 27 Sep 2005, 03:15
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
If j and k are positive integers, j – 2 is divisible by 4 and k – 5 is divisible by 4, all of the following could be the value of j – k EXCEPT:


43

33

21

13

5
_________________

"To win the battle you need to last 15 minutes longer than your enemies"

VP
VP
User avatar
Joined: 13 Jun 2004
Posts: 1128
Location: London, UK
Schools: Tuck'08
Followers: 6

Kudos [?]: 23 [0], given: 0

GMAT Tests User
 [#permalink] New post 27 Sep 2005, 05:16
I made 2 lists of potential numbers. I found 43 is not possible.
Senior Manager
Senior Manager
avatar
Joined: 30 Oct 2004
Posts: 289
Followers: 1

Kudos [?]: 5 [0], given: 0

GMAT Tests User
 [#permalink] New post 27 Sep 2005, 05:22
Yup.. 43 here too.

Here's my explanation

j>0, k>0
Also, j-2 = 4X (some number X since j-2 is a multiple of 4)
k-5 = 4Y (same reasoning)
Combining the two we get

j-k = (X-Y)(4) - 3 => j-k = A - 3 (some number A, which is 4(X-Y))

In the list of answers... add 3 to all... The one that in NOT a multiple of 4 is the answer. 43 + 3 = 46 is not a multiple of 4.
_________________

-Vikram

Manager
Manager
avatar
Joined: 06 Aug 2005
Posts: 198
Followers: 3

Kudos [?]: 5 [0], given: 0

GMAT Tests User
 [#permalink] New post 27 Sep 2005, 06:16
It is just modulo 4 arithmetic.

(j-2)= 0 mod 4
So j = 2 mod 4

(k-5) = 0 mod 4
So k = 5 mod 4 = 1 mod 4

j-k = (2-1) mod 4 = 1 mod 4

43 = 3 mod 4.
So j-k <> 43
Senior Manager
Senior Manager
User avatar
Joined: 14 Apr 2005
Posts: 422
Location: India, Chennai
Followers: 1

Kudos [?]: 3 [0], given: 0

GMAT Tests User
Re: PS [#permalink] New post 28 Sep 2005, 04:17
Macedon wrote:
If j and k are positive integers, j – 2 is divisible by 4 and k – 5 is divisible by 4, all of the following could be the value of j – k EXCEPT:


43

33

21

13

5

My answer is A, and my work is as below.
j-2= 0 mod 4; k-5= 0 mod 4
=> j-k= 3 + 0 mod 4 or j-k = 1 mod 4
5 when divided by 4 gives remainder 1,
21 when divided by 4 gives remainder 1,
33 when divided by 4 gives remainder 1,
43 when divided by 4 gives remainder 3, and hence the answer is 43.
Re: PS   [#permalink] 28 Sep 2005, 04:17
    Similar topics Author Replies Last post
Similar
Topics:
Experts publish their posts in the topic If j and k are positive integers and j + k is odd guerrero25 2 04 Feb 2014, 07:53
If j and k are positive integers such that k > j AkshayChittoria 0 05 Sep 2013, 22:32
15 If j and k are positive integers, j - 2 is divisible by 4 gmat1220 11 17 Apr 2011, 10:43
If j and k are positive integers where k > j, what is the lan583 3 22 Sep 2006, 13:02
If j and k are positive integers where k > j, what is the duttsit 7 08 Aug 2006, 14:49
Display posts from previous: Sort by

If j and k are positive integers, j 2 is divisible by 4

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.