If Jack bought a computer for $1000 more than a generic mode

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If Jack bought a computer for $1000 more than a generic mode [#permalink]

30 Sep 2012, 22:26

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If Jack bought a computer for $1000 more than a generic model, then the price of that computer would have been 8 times the value of the accompanying bonus wireless router, which is 1/4th the price of the generic model. What is the price of the computer?

I've translated the words into the equations but can't approach it. Please help..

Here's what I did:
c = $1000 + g
c = 8b
b = (1/4) g

Thanks!

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Re: If Jack bought a computer for $1000 more than a generic mode [#permalink]

30 Sep 2012, 22:45

rainbooow wrote:

Continuing your approach and replace b with 1/4g in c= 8b
We get c = 2g
We also have c = 1000 + g
Equating, we get 2g = 1000 + g => g = 1000
Hence, the price of the computer = 2g = $2000
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Re: If Jack bought a computer for $1000 more than a generic mode [#permalink]

30 Sep 2012, 23:13

Сicerone, well done! Thank you for ur quick answer!

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Re: If Jack bought a computer for $1000 more than a generic mode [#permalink]

01 Oct 2012, 04:55

c = $1000 + g is correct C = g + 1000

seems the same but the correct translation is the second one

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Re: If Jack bought a computer for $1000 more than a generic mode [#permalink]

01 Oct 2012, 05:17

carcass wrote:

c = $1000 + g is correct C = g + 1000

seems the same but the correct translation is the second one

I like them both :wink:

Re: If Jack bought a computer for $1000 more than a generic mode [#permalink] 01 Oct 2012, 05:17

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If Jack bought a computer for $1000 more than a generic mode

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If Jack bought a computer for $1000 more than a generic mode

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