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If Jack bought a computer for $1000 more than a generic mode

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Joined: 10 Jun 2012
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If Jack bought a computer for $1000 more than a generic mode [#permalink] New post 30 Sep 2012, 21:26
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If Jack bought a computer for $1000 more than a generic model, then the price of that computer would have been 8 times the value of the accompanying bonus wireless router, which is 1/4th the price of the generic model. What is the price of the computer?

I've translated the words into the equations but can't approach it. Please help..

Here's what I did:
c = $1000 + g
c = 8b
b = (1/4) g

Thanks!
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Re: If Jack bought a computer for $1000 more than a generic mode [#permalink] New post 30 Sep 2012, 21:45
rainbooow wrote:
If Jack bought a computer for $1000 more than a generic model, then the price of that computer would have been 8 times the value of the accompanying bonus wireless router, which is 1/4th the price of the generic model. What is the price of the computer?

I've translated the words into the equations but can't approach it. Please help..

Here's what I did:
c = $1000 + g
c = 8b
b = (1/4) g

Thanks!


Continuing your approach and replace b with 1/4g in c= 8b
We get c = 2g
We also have c = 1000 + g
Equating, we get 2g = 1000 + g => g = 1000
Hence, the price of the computer = 2g = $2000
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Re: If Jack bought a computer for $1000 more than a generic mode [#permalink] New post 30 Sep 2012, 22:13
Сicerone, well done! Thank you for ur quick answer!
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Re: If Jack bought a computer for $1000 more than a generic mode [#permalink] New post 01 Oct 2012, 03:55
Expert's post
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Re: If Jack bought a computer for $1000 more than a generic mode [#permalink] New post 01 Oct 2012, 04:17
carcass wrote:
c = $1000 + g is correct C = g + 1000

seems the same but the correct translation is the second one ;)



I like them both :wink:
Re: If Jack bought a computer for $1000 more than a generic mode   [#permalink] 01 Oct 2012, 04:17
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