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If Jake loses 8 pounds, he will weigh twice as much as his

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If Jake loses 8 pounds, he will weigh twice as much as his [#permalink] New post 30 May 2008, 09:56
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If Jake loses 8 pounds, he will weigh twice as much as his sister. Together they now weigh 278 pounds. What is Jake’s present weight, in pounds?

(A) 131
(B) 135
(C) 139
(D) 147
(E) 188
[Reveal] Spoiler: OA
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Re: weight problem [#permalink] New post 30 May 2008, 10:08
sportypk wrote:
If Jake loses 8 pounds, he will weigh twice as much as his
sister. Together they now weigh 278 pounds. What is Jake’s
present weight, in pounds?
(A) 131
(B) 135
(C) 139
(D) 147
(E) 188

the OA is 188...could anyone explain how?


Heyyy
Lets say J is the weight of Jack and S is the wt of his sister.
If he loses 8 pounds, he s twice as heavy as his sister.
J-8=2*S
Also, together they weight 278 pounds
J+S=278

solvong the 2 equation ,we get J=188 pounds !

Cheers !
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Re: weight problem [#permalink] New post 30 May 2008, 10:14
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Consider Sister weight Now as x
Jakes weight (2times +8) = 2x+8

(2x+8)+(x) =278
x=90

Jake's weight is ....188
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Re: If Jake loses 8 pounds, he will weigh twice as much as his [#permalink] New post 14 Jan 2013, 13:03
sportypk wrote:
If Jake loses 8 pounds, he will weigh twice as much as his
sister. Together they now weigh 278 pounds. What is Jake’s
present weight, in pounds?
(A) 131
(B) 135
(C) 139
(D) 147
(E) 188

the OA is 188...could anyone explain how?


My solution is:
(278-8)/3 = 90
90*2+8= 188
Re: If Jake loses 8 pounds, he will weigh twice as much as his   [#permalink] 14 Jan 2013, 13:03
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