If Juan takes 11 seconds to run y yards, how many seconds will it take

Since t = 11 seconds represents time, one can immediately eliminate answers C,D and E, because they don't have units of time.
(C) x/(ty) has units of 1/time
(D) t/(xy) has units of time/speed squared, which finally is time cubed/distance squared
(E) xy/t has units of speed squared/time, which finally is distance squared/time cubed

To choose between (A) and (B), we should keep in mind that time is distance/speed. Since the distance in our case is x, it should appear in the numerator.

Hence, Answer A.

y yard s for 11 second
x yards for 11x/y second
so answer is A

If you don't want to do fancy calculations you can just pick numbers...

y = 1
x = 2

And the questions re-phrased would be:

If Juan takes 11 seconds to run 1 yards, how many seconds will it take him to run 2 yards at the same rate?

It will take him 22 seconds to run 2 yards. Now just use those x and y values in the answers and find the one that equals 22 (which is B).

y yards-------------- 11 seconds
x yards ------------- ? seconds

(11*x)/y seconds

This was an easy one, but I do have a questions concerning rates.

When is it that we HAVE to find the rate at which 1 unit of work is done, in order to calculate another rate?

I hope my question is understandable...

Thank you,
Natalia

If you construct a table which is like the one given below it will be clear to you what you have been given and what you need to find out what is asked. For this question,
R * T = D
? * 11 = y

and we need to find out

R * T = D
? * ? = x
you need the rate here to find out the time.That as specified by the question is the same as the first case. So R=y/11.
So time=x/(y/11)=11x/y.

Kudos please if this helped anyhow.

This problem is testing us on the Rate x Time = Distance relationship. This relationship also tells us that Rate = Distance/Time and Time = Distance/Rate.

Ultimately, we are looking for how many seconds it will take Juan to run x yards. Thus, the equation we’ll use is: Time = Distance/Rate. We know the distance is x yards, and we need to find Juan’s rate.

We can find Juan’s rate as follows: Rate = Distance/Time = y yards/11 seconds

Using that rate, we need to determine how long it takes him to run x yards at the same rate. So we have:

Time = Distance/Rate

Time = x yards/(y yards/11 seconds)

Time = (x yards) x (11 seconds/y yards)

Time = 11x/y seconds

Answer A.

Using ratios we can write:
\(\frac{11}{y}=\frac{something}{x}\)
\(Something = \frac{11x}{y}\)

Answer is A

To travel y yard it takes 11 sec I.e
Y yard= 11 sec
1 yard= 11/Y sec
X yard= 11X/Y

Answer is A

Posted from my mobile device

Hi All,

We're told that it takes Juan 11 seconds to run Y yards. We're asked how many seconds it takes him to run X yards at that same rate. This question can be solved by TESTing VALUES.

IF....
Y = 2
X = 4

Then Juan takes 11 seconds to run 2 yards. At that same rate, he would need 22 seconds to run 4 yards. So we're looking for an answer that = 22 when Y = 2 and X = 4...

Answer A: 11X/Y = 44/2 = 22 This IS a match
Answer B: 11Y/X = 22/4 NOT a match
Answer C: X/(11Y) = 2/44 NOT a match
Answer D: 11/(XY) = 11/8 NOT a match
Answer E: (XY)/11 = 8/11 NOT a match

Final Answer:

GMAT assassins aren't born, they're made,
Rich

Let's solve the question using the input-output approach.

For example, let's let y = 22
This means that Juan takes 11 seconds to run 22 yards, which means his speed is 2 yards per second.

From here, if we let x = 10, then the question is asking,"how many seconds will it take Juan to run 10 yards at the same rate (of 2 yards per second)?"
Well, at that speed, it will take Juan 5 seconds to run 10 yards.

In other words, if we INPUT y = 22 and x = 10, then the answer (the OUTPUT) to the question is 5.

Now we'll plug y = 22 and x = 10 into the answer choices and see which one yields the OUTPUT of 5
(A) 11x/y = (11)(10)/22 = 5 GREAT!
(B) 11y/x = (11)(22)/10 = something other than 5 ELIMINATE B
(C) x/11y = (10)/(11)(22) = something other than 5 ELIMINATE C
(D) 11/xy (11)/(10)(22) = 1/20 ELIMINATE D
(E) xy/11 = (10)(22)/(11) = 20 ELIMINATE E

Answer: A

Cheers,
Brent

Another option is to use equivalent ratios.

The ratio is time/distance

For every 11 seconds, Juan can run y yards
So we get the ratio 11/y

Let T = the time it takes to run x yards.
That is, For every T seconds, Juan can run x yards
We get the ratio T/x

Since Juan runs at a constant rate, we can write: we get: 11/y = T/x
Cross multiply to get: 11x = Ty
Divide both sides by y to get: 11x/y = T
So, the answer is A

Cheers,
Brent

time Distance
11 y
t x

cross multiply, 11x = ty
t=11x/y

Option A

Solution

Given

• Juan takes 11 seconds to run y yards

To find

• The time juan will take to run x yards at the same rate

Approach and Working out

• If the rate is same then to run y yards-> time taken 11sec

o So, to run 1 yard -> time taken 11/y sec
o To run x yards-> 1*x yards -> time taken 11x/y sec

Hence, option A is the correct answer.

Correct Answer: Option A

To determine how many seconds it will take Juan to run x yards at the same rate, we can set up a proportion using the given information.

We know that Juan takes 11 seconds to run y yards. Let's set up the proportion:

y yards / 11 seconds = x yards / t seconds

Here, t represents the number of seconds it will take Juan to run x yards.

To solve for t, we can cross-multiply the proportions:

y * t = 11 * x

Now, we can divide both sides of the equation by y to isolate t:

t = (11 * x) / y

So, the answer is (A) 11x/y.