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Each week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation.

Re: If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink]
10 Mar 2015, 19:07

Why do we automatically assume there are parentheses around (3-2k^2)? I didn't assume that so then I didn't distribute the negative on the outside which of course then gave me answer A.

Re: If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink]
10 Mar 2015, 19:28

1

This post received KUDOS

soniasawhney wrote:

Why do we automatically assume there are parentheses around (3-2k^2)? I didn't assume that so then I didn't distribute the negative on the outside which of course then gave me answer A.

hi soniasawhney.. it does not require any parenthesis as any sign in front of a fraction modifies the entire fraction irrespective of the term.. just an example.. let the fraction be - \(\frac{7-9}{2}\).. two ways to do it .. first change signs first and then find answer... \(\frac{-7+9}{2}\)=\(\frac{2}{2}\)=1...

second simplify and then change the signs... - \(\frac{7-9}{2}\)=- \(\frac{-2}{2}\)=-(-1)=1..

so both ways answer is same, which means parentheses is not required and a sign in front of a fraction automatically means that the entire fraction is inside bracket....

Re: If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink]
10 Mar 2015, 20:24

1

This post received KUDOS

Expert's post

soniasawhney wrote:

Why do we automatically assume there are parentheses around (3-2k^2)? I didn't assume that so then I didn't distribute the negative on the outside which of course then gave me answer A.

To clarify further: There are 3 ways in which you can make a fraction negative \(\frac{-3}{5}\)

\(-\frac{3}{5}\) Take this to mean \(\frac{-3}{5}\)

and \(\frac{3}{-5}\)

Each one of these fractions is the same as \(\frac{-3}{5}\)

Now what happens in case you have multiple terms in numerator:

\(\frac{-x + 2}{4}\) The negative is only in front of x.

\(-\frac{x+2}{4}\) The negative is in effect, in front of the entire numerator. So this is the same as \(\frac{-(x+2)}{4}\) _________________

Re: If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink]
12 Mar 2015, 18:40

Mountain14 wrote:

After Solving the equation , I got A

Because you didn't distribute the first negative sign on the first fraction. I made the same mistake. 8th grade rules but still find them hard to remember. _________________

"Hardwork is the easiest way to success." - Aviram

One more shot at the GMAT...aiming for a more balanced score.

Each week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation.

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Given that, k - (3 - 2k^2)/k = x/k Take LCM of denominators, So, [k^2 - (3 - 2k^2)]/k = x/k So, [k^2 - 3 + 2k^2]/k = x/k Canceling out k from the denominators of both sides, So, [k^2 - 3 + 2k^2] = x So, 3k^2 - 3 = x Hence option C.

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