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If k#0 and k - (3 -2k^2)/k = x/k, then x =

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If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink] New post 24 Feb 2014, 22:50
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The Official Guide For GMAT® Quantitative Review, 2ND Edition

If \(k\neq{0}\) and \(k - \frac{3 -2k^2}{k} = \frac{x}{k}\), then x =

(A) -3 - k^2
(B) k^2 -3
(C) 3k^2 - 3
(D) k - 3 - 2k^2
(E) k - 3 + 2k^2

Problem Solving
Question: 111
Category: Algebra Second-degree equations
Page: 76
Difficulty: 500


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Re: If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink] New post 24 Feb 2014, 22:50
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SOLUTION

If \(k\neq{0}\) and \(k - \frac{3 -2k^2}{k} = \frac{x}{k}\), then x =

(A) -3 - k^2
(B) k^2 -3
(C) 3k^2 - 3
(D) k - 3 - 2k^2
(E) k - 3 + 2k^2

\(k - \frac{3 -2k^2}{k} = \frac{x}{k}\);

Multiply by k: \(k^2 - (3 -2k^2) = x\);

\(x=3k^2-3\).

Answer: C.
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Re: If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink] New post 25 Feb 2014, 04:10
After Solving the equation , I got A
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Re: If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink] New post 25 Feb 2014, 22:26
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k - \frac{3 -2k^2}{k} = \frac{x}{k};
After simplifying and canceling k in the denominator, we get: k^2 - 3 + 2k^2 = x;
3k^2 - 3 = x;

Ans is (C).
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Re: If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink] New post 26 Feb 2014, 01:10
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Option C.
k-(3-2k^2)/k=x/k
Multiply both sides by k
k^2-3+2k^2=x
3k^2-3=x
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Re: If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink] New post 26 Feb 2014, 01:28
Thank You for kudos,WoundedTiger!
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Re: If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink] New post 01 Mar 2014, 03:12
Expert's post
SOLUTION

If \(k\neq{0}\) and \(k - \frac{3 -2k^2}{k} = \frac{x}{k}\), then x =

(A) -3 - k^2
(B) k^2 -3
(C) 3k^2 - 3
(D) k - 3 - 2k^2
(E) k - 3 + 2k^2

\(k - \frac{3 -2k^2}{k} = \frac{x}{k}\);

Multiply by k: \(k^2 - (3 -2k^2) = x\);

\(x=3k^2-3\).

Answer: C.
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COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink] New post 08 Jul 2014, 21:17
Bunuel wrote:
SOLUTION

If \(k\neq{0}\) and \(k - \frac{3 -2k^2}{k} = \frac{x}{k}\), then x =

(A) -3 - k^2
(B) k^2 -3
(C) 3k^2 - 3
(D) k - 3 - 2k^2
(E) k - 3 + 2k^2

\(k - \frac{3 -2k^2}{k} = \frac{x}{k}\);

Multiply by k: \(k^2 - (3 -2k^2) = x\);

\(x=3k^2-3\).

Answer: C.


I just added a step after the highlighted one to remove -ve sign :) . Rest all did same

\(k - \frac{3 -2k^2}{k} = \frac{x}{k}\);

\(k + \frac{2k^2 - 3}{k} = \frac{x}{k}\)
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Re: If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink] New post 08 Jul 2014, 22:55
Expert's post
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

If \(k\neq{0}\) and \(k - \frac{3 -2k^2}{k} = \frac{x}{k}\), then x =

(A) -3 - k^2
(B) k^2 -3
(C) 3k^2 - 3
(D) k - 3 - 2k^2
(E) k - 3 + 2k^2





You can also put in k = 1 in \(k - \frac{3 -2k^2}{k} = \frac{x}{k}\) to get x = 0.
When you put k = 1 in options, only (C) and (E) give x = 0.

Now put k = -1 in \(k - \frac{3 -2k^2}{k} = \frac{x}{k}\) to get x = 0.
When you put k = -1 in options, only (C) gives x = 0
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Re: If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink] New post 10 Mar 2015, 19:07
Why do we automatically assume there are parentheses around (3-2k^2)? I didn't assume that so then I didn't distribute the negative on the outside which of course then gave me answer A.
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Re: If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink] New post 10 Mar 2015, 19:28
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soniasawhney wrote:
Why do we automatically assume there are parentheses around (3-2k^2)? I didn't assume that so then I didn't distribute the negative on the outside which of course then gave me answer A.


hi soniasawhney..
it does not require any parenthesis as any sign in front of a fraction modifies the entire fraction irrespective of the term..
just an example..
let the fraction be - \(\frac{7-9}{2}\)..
two ways to do it ..
first change signs first and then find answer...
\(\frac{-7+9}{2}\)=\(\frac{2}{2}\)=1...

second simplify and then change the signs...
- \(\frac{7-9}{2}\)=- \(\frac{-2}{2}\)=-(-1)=1..

so both ways answer is same, which means parentheses is not required and a sign in front of a fraction automatically means that the entire fraction is inside bracket....
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Re: If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink] New post 10 Mar 2015, 20:24
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soniasawhney wrote:
Why do we automatically assume there are parentheses around (3-2k^2)? I didn't assume that so then I didn't distribute the negative on the outside which of course then gave me answer A.


To clarify further:
There are 3 ways in which you can make a fraction negative
\(\frac{-3}{5}\)

\(-\frac{3}{5}\) Take this to mean \(\frac{-3}{5}\)

and \(\frac{3}{-5}\)

Each one of these fractions is the same as \(\frac{-3}{5}\)

Now what happens in case you have multiple terms in numerator:

\(\frac{-x + 2}{4}\) The negative is only in front of x.

\(-\frac{x+2}{4}\) The negative is in effect, in front of the entire numerator. So this is the same as \(\frac{-(x+2)}{4}\)
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Re: If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink] New post 12 Mar 2015, 18:40
Mountain14 wrote:
After Solving the equation , I got A


Because you didn't distribute the first negative sign on the first fraction. I made the same mistake. 8th grade rules but still find them hard to remember.
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Re: If k#0 and k - (3 -2k^2)/k = x/k, then x = [#permalink] New post 12 Mar 2015, 22:12
Expert's post
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

If \(k\neq{0}\) and \(k - \frac{3 -2k^2}{k} = \frac{x}{k}\), then x =

(A) -3 - k^2
(B) k^2 -3
(C) 3k^2 - 3
(D) k - 3 - 2k^2
(E) k - 3 + 2k^2

Problem Solving
Question: 111
Category: Algebra Second-degree equations
Page: 76
Difficulty: 500


GMAT Club is introducing a new project: The Official Guide For GMAT® Quantitative Review, 2ND Edition - Quantitative Questions Project

Each week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project:
1. Please provide your solutions to the questions;
2. Please vote for the best solutions by pressing Kudos button;
3. Please vote for the questions themselves by pressing Kudos button;
4. Please share your views on difficulty level of the questions, so that we have most precise evaluation.

Thank you!


Given that,
k - (3 - 2k^2)/k = x/k
Take LCM of denominators,
So, [k^2 - (3 - 2k^2)]/k = x/k
So, [k^2 - 3 + 2k^2]/k = x/k
Canceling out k from the denominators of both sides,
So, [k^2 - 3 + 2k^2] = x
So, 3k^2 - 3 = x
Hence option C.

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Re: If k#0 and k - (3 -2k^2)/k = x/k, then x =   [#permalink] 12 Mar 2015, 22:12
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