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If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe

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If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe [#permalink] New post 14 May 2013, 20:44
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Question Stats:

72% (02:04) correct 28% (02:01) wrong based on 72 sessions
If k > 0, x + k = y, and y + 3k = z, what is the ratio between z - x and y - x ?

(A) 1 to 4
(B) 1 to 2
(C) 2 to 1
(D) 3 to 1
(E) 4 to 1
[Reveal] Spoiler: OA

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Last edited by Bunuel on 03 Oct 2013, 23:01, edited 1 time in total.
Edited the question.
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Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe [#permalink] New post 14 May 2013, 20:54
manishuol wrote:
If k > 0, x + k = y, and y + 3k = z, what is the ratio between z � x and y � x ?

(A) 1 to 4
(B) 1 to 2
(C) 2 to 1
(D) 3 to 1
(E) 4 to 1


The question is not clear, all I can see is a question mark:
z � x and y � x

Can you repost this?
Or is this z?x and y?x the actual question?
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Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe [#permalink] New post 14 May 2013, 22:23
psychout wrote:
manishuol wrote:
If k > 0, x + k = y, and y + 3k = z, what is the ratio between z � x and y � x ?

(A) 1 to 4
(B) 1 to 2
(C) 2 to 1
(D) 3 to 1
(E) 4 to 1


The question is not clear, all I can see is a question mark:
z � x and y � x

Can you repost this?
Or is this z?x and y?x the actual question?



This is How the Question is ............
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Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe [#permalink] New post 15 May 2013, 00:29
manishuol wrote:
If k > 0, x + k = y, and y + 3k = z, what is the ratio between z � x and y � x ?

(A) 1 to 4
(B) 1 to 2
(C) 2 to 1
(D) 3 to 1
(E) 4 to 1

Hi,

From the answer, I could only assume that "z � x" is z-x.
So, (z-x)/(y-x) = 4k/k = 4:1
thus (E)

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Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe [#permalink] New post 02 Oct 2013, 11:07
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If k > 0, x + k = y, and y + 3k = z, what is the ratio between z � x and y � x ?

(A) 1 to 4
(B) 1 to 2
(C) 2 to 1
(D) 3 to 1
(E) 4 to 1


Picking numbers is probably the fastest solution to solve this problem. First, k>0 = k could be ANY positive number. For the purposes of the explanation K= 2. x + 2 = y and y + 3(2) = z. Rearrange the latter equation as to isolate y.

X + 2 = Y
Z - 6 = Y

Now pick Any number for Y. For the sake of our example Y will be 10. Now the equation looks like:

X + 2 = 10
Z - 6 = 10

Solve for X. Solve for Z. X= 8 and Z = 16

what is the ratio between z � x and y � x
16 to 8 as 10 to 8
8 2
8/2 = 4 2/2=1

Thus answer choice E is correct- 4 to 1.
Kudos please :roll:
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Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe [#permalink] New post 03 Oct 2013, 20:11
cmclaurin wrote:

what is the ratio between z � x and y � x
16 to 8 as 10 to 8
8 2
8/2 = 4 2/2=1

Thus answer choice E is correct- 4 to 1.


Could you please elaborate on how you got 8 2 and further?
thanks
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Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe [#permalink] New post 03 Oct 2013, 20:27
16 - 8 = 8

10 - 8 = 2

I hope this is helpful now. Lol (I'm being a troll). Thanks
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Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe [#permalink] New post 03 Oct 2013, 22:51
Expert's post
manishuol wrote:
If k > 0, x + k = y, and y + 3k = z, what is the ratio between z � x and y � x ?

(A) 1 to 4
(B) 1 to 2
(C) 2 to 1
(D) 3 to 1
(E) 4 to 1


Assuming that the required ratio is (z - x)/(y - x),

x + k = y
y - x = k

y + 3k = z
x + k + 3k = z
z - x = 4k

(z - x)/(y - x) = 4/1
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Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe [#permalink] New post 04 Oct 2013, 22:31
(z-x )/ (y-x) == (y + 3k -x )/ (y-x) where k = y-x

hence == (y-x) + 3(y-x) / ( y-x) = 4(y-x)/(y-x) == 4/1 !!
Re: If k > 0, x + k = y, and y + 3k = z, what is the ratio betwe   [#permalink] 04 Oct 2013, 22:31
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