Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

But 6 is divisible by an odd integer other than 1. It's divisible by 3.

The only positive integers greater than 1 that don't have any odd factors greater than 1 are powers of 2. So statement 2 is sufficient on its own.

... And once again I just answered my own question. (I feel dumb now). I'd initially answered D, thinking that statement 1 was also sufficient in itself. But of course, 192 is a multiple of 64, and 192 is not a power of 2. So D is wrong. B it is.

But 6 is divisible by an odd integer other than 1. It's divisible by 3.

The only positive integers greater than 1 that don't have any odd factors greater than 1 are powers of 2. So statement 2 is sufficient on its own.

... And once again I just answered my own question. (I feel dumb now). I'd initially answered D, thinking that statement 1 was also sufficient in itself. But of course, 192 is a multiple of 64, and 192 is not a power of 2. So D is wrong. B it is.

You right. This is really tricky if one doesnt know these number system properties (especially if she is not good in number picking like me).

II) states that it is not divisible by any odd number > 1, which implies k is even. however, what we need to say if K is a power of 2. For example, 10 is even , but is not a power of 2. I am assuming here that the notation, 2^ r , denotes, 2 raised to r and not 2 multiplied by r.

From statement 1, we're told k is a multiple of 2^6. This could be 3(2^6), 4(2^6). Since there are so many values of k, we can't tell.

From statement 2, we're told k is not divisbile by any odd integer greater than 1. This means k is even and a power of 2. Any other even number that has a prime factor other than 2 will be divisible by any odd integer > 1. For e.g., if k=18, then 18 = 3*3*2. It's divisible by 3. However, if k = 16, then 2^4 and this is equal to 2^r if r is 4.

The answer B is correct if we're asked if k can be represented in the form 2^r where r is a positive value.

However, we're asked here if k EQUALS 2^r and we do not have information for r.

I opted to do my Team-Based Discussion (TBD) and interview in London with a member of the Admissions office. It was a benefit to have been through the...

After so many confusing thoughts, I decided to write this post. I am yet to finalize the list of B-Schools I am applying to. For a background check, I...