If K is not equal to 1, 0 or -1 , is 1/k>0 1) 1/k-1>0

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If K is not equal to 1, 0 or -1 , is 1/k>0 1) 1/k-1>0 [#permalink]

20 Nov 2006, 20:26

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If K is not equal to 1, 0 or -1 , is 1/k>0

1) 1/k-1>0

2) 1/k+1>0
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20 Nov 2006, 22:36

A

From 1, 1/k-1 > 0, add 1 on both sides, we get 1/k>1 which implies 1/k>0

From 2, 1/k+1>0 i.e. 1/k > -1 , INSUFF

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D [#permalink]

20 Nov 2006, 23:54

if K is not equal to 1, 0 or -1 , is 1/k>0

1) 1/k-1>0

2) 1/k+1>0

Sub k = -3 then 1 / ( -3-1) = -1/4 i.e. not greater than zero so cant be -3
sub k=2 then 1 / ( 2-1) =1 i.e. greater than zero

so 1/k-1>0 implies k is +ve value that means 1/k > 0 suff

use ame logic and is uff 2
answer D

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21 Nov 2006, 00:30

1)1/k-1>0
1/k>1
1>k
k<1... however we do not know whether K is positive or negative...

Insufficient

2)1/k+1>0

1/k>-1
1>-k
-1<k
k>-1.... however we do not know whether it is positive or negative...

Both together:

1/k-1>0
1/k+1>0

Add both equations together:

2/k>0....k must be positive...

Thus C...

And three different answer choices

[EDIT]
.
.
.
.
.

Ammending my answer choice to A

Yes, if 1/k>1.... we should have no doubts any more... k is positive....

[#permalink] 21 Nov 2006, 00:30

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If K is not equal to 1, 0 or -1 , is 1/k>0 1) 1/k-1>0

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If K is not equal to 1, 0 or -1 , is 1/k>0 1) 1/k-1>0

If K is not equal to 1, 0 or -1 , is 1/k>0 1) 1/k-1>0

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