|
Author |
Message |
|
TAGS:
|
|
|
Senior Manager
Joined: 10 Dec 2004
Posts: 277
Followers: 1
Kudos [?]:
0
[0], given: 0
|
If k, m, and t are positive integers and k/6 + m/4 = t/12 , [#permalink]
 23 Feb 2005, 20:07
Question Stats:
0% (00:00) correct
 0% (00:00) wrong based on 0 sessions
If k, m, and t are positive integers and k/6 + m/4 = t/12 , do t and 12 have a common factor greater than 1 ?
(1) k is a multiple of 3.
(2) m is a multiple of 3.
|
|
|
|
|
|
|
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5134
Location: Singapore
Followers: 9
Kudos [?]:
87
[0], given: 0
|
we can simplify the equation to 2K+3M = t
(1) tells us nothing about M. - not sufficient.
(2) tells us nothing about K. - not sufficine.t
Using (1) and (2),
we know t = 2K + 3M
3M is going ot be a multiple of 3 (3 * multiple of 3)
2K is also going ot be a multple of 3 (2* multiple of 3)
So 12 and t do have at least one more common factor. That is 3.
(C)
|
|
|
|
|
|
Senior Manager
Joined: 10 Dec 2004
Posts: 277
Followers: 1
Kudos [?]:
0
[0], given: 0
|
It does tell m is a positive integer...
ie. m>0
|
|
|
|
|
|
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5134
Location: Singapore
Followers: 9
Kudos [?]:
87
[0], given: 0
|
2K+3M = t
(1) 2k is a multiple of 3 (2*multiple of 3) but we know M is greater than 1. And thus 3M is also a multiple of 3. So we can tell that t does have more than one common factor.
Same with (2).
Should be (D). My bad.. didn't read the question properly
|
|
|
|
|
|
Director
Joined: 19 Nov 2004
Posts: 589
Location: SF Bay Area, USA
Followers: 2
Kudos [?]:
7
[0], given: 0
|
k/6 + m/4 = t/12
simplifying,
2k+3m = t
1) k is a multiple of 3.
2*3*x + 3m = t
3(2x + 3m)= t
3 is a factor of t
=> t and 12 have 3 as a common factor - yes
2) m is a multiple of 3.
2k + 3*3*y = t
can't derive much with this about factors of t.
A) it is
|
|
|
|
|
|
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5134
Location: Singapore
Followers: 9
Kudos [?]:
87
[0], given: 0
|
nice method nocilis.. i ought to hammer myself. Only god knoww what i'm thinking of making mistakes twice in a row. 
|
|
|
|
|
|
Senior Manager
Joined: 10 Dec 2004
Posts: 277
Followers: 1
Kudos [?]:
0
[0], given: 0
|
"A" it is.
Although I solved it by substituition , takes lot longer.
_________________
"Forums are meant to benefit all. No one is interested in knowing what your guesses are. Please explain the reasoning behind the answer you chose. This will also help you organize your thoughts quickly during the exam."
|
|
|
|
|
|
SVP
Joined: 03 Jan 2005
Posts: 2322
Followers: 9
Kudos [?]:
157
[0], given: 0
|
ywilfred also has a nice method, you just have to be a bit more careful.  (I'm often the same as you.  )
|
|
|
|
|
|
SVP
Joined: 18 Nov 2004
Posts: 1544
Followers: 2
Kudos [?]:
9
[0], given: 0
|
"A"
simplify we get 2k+3m = t
state I......k = 3n.......6n+3m = t.....3(2n+m) = t.....ans is yes as t has 3 as a factor....suff
state II.....m = 3n.....2k+9n = t.....for k= 1 and n=1.....t = 11....ans NO.....for k= 1 and n = 2.....t = 20...ans YES...insuff
|
|
|
|
|
|
Manager
Joined: 01 Jan 2005
Posts: 169
Location: NJ
Followers: 1
Kudos [?]:
0
[0], given: 0
|
A.
I) k is a mutilple of 3 and 3m is also a multiple of 3 thus 2k + 3m that is t is also a multiple of 3... suff
II) Doesn't give us anyhting common to derive.. insuff
|
|
|
|
|
|
Manager
Joined: 01 Feb 2005
Posts: 79
Location: NYC
Followers: 1
Kudos [?]:
0
[0], given: 0
|
One more A
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
Similar topics |
Author |
Replies |
Last post |
|
Similar
Topics:
|
 |
|
|
If k,m, and t are positive integers and k/6+m/4=t/12 , do t
|
falcor |
2 |
16 Sep 2004, 08:42 |
|
|
|
|
If k, m, and t are positive integers and (k/6)+(m/4) =(t/12)
|
apollo168 |
3 |
24 Aug 2006, 10:43 |
|
|
1
|
|
If k, m, and t are positive integers and k/6 + m/4 = t/12 ,
|
leonidas |
5 |
07 Oct 2008, 23:07 |
 |
3
|
 |
If k, m, and t are positive integers and k/6 + m/4 = t/12 ,
|
marine |
35 |
05 Sep 2004, 03:10 |
|
|
2
|
|
If k, m, and t are positive integers and k/6 + m/4 = t/12
|
Stiv |
3 |
23 Feb 2012, 02:28 |
|
|
|
|
|
|
close
