If L <> 0 , is an integer? a. (K^2) / (L^2) is an

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If L <> 0 , is an integer? a. (K^2) / (L^2) is an [#permalink]

09 May 2010, 03:28

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If L <> 0 , is [(18 * K ) / L ] an integer?

a. (K^2) / (L^2) is an integer.
b. K - L = L

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Re: DS integer [#permalink]

09 May 2010, 04:10

msand wrote:

If L does not equal to 0, is (18*K)/L an integer?

(1) K^2/L^2 is an integer.
(2) K-L=L

If l\neq{0} is \frac{18k}{l}=integer?

(1) \frac{k^2}{l^2}=integer. k=4 and l=2 - answer YES but k=\sqrt{6} and l=\sqrt{2} - answer NO. Not sufficient.

(2) k=2l --> \frac{18k}{l}=\frac{18*2l}{l}=36=integer. Sufficient.

Answer: B.
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Manager

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Re: DS integer [#permalink]

16 May 2010, 12:32

according to statement A K^2/L^2 is integer but that doesn't mean that K & L are integer; square of 1.732 is 3 which is an integer but 1.732 itself is not a integer. hence statement A - i nsufficient

statment B - k=2l sufficeint we get a integer from it
so B must be the answer.

Re: DS integer [#permalink] 16 May 2010, 12:32

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If L <> 0 , is an integer? a. (K^2) / (L^2) is an

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If L <> 0 , is an integer? a. (K^2) / (L^2) is an

If L <> 0 , is an integer? a. (K^2) / (L^2) is an

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