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If L and K are lines in xy- plane, is the product of the

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If L and K are lines in xy- plane, is the product of the [#permalink] New post 31 Jan 2008, 18:24
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If L and K are lines in xy- plane, is the product of the slope of L and K equal to -1?

(1) Line L passes through the origin and the point (1,2).
(2) Line K has x-intercept 4 and y-intercept 2.
[Reveal] Spoiler: OA
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Re: DS - if l and k [#permalink] New post 31 Jan 2008, 20:15
blog wrote:
If l and K are lines in xy- plane, is the product of the slope of l and k equal to -1?

1. Line l passes through the origin and the point (1,2).
2. Line K has x-intercept 4 and y-intercept 2.



C


1: we dont know anything about the other line but we can find the slope of line l = 2

2: again we dont know the other line's slope but k's is -1/2

Together 2*-1/2= -1

But you could just realize that 1 and 2 are suff together b/c we know the slopes we are going to get a YES OR A NO NOT BOTH. so u could save some time.
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Re: DS - if l and k [#permalink] New post 01 Feb 2008, 09:55
blog wrote:
GMATBLACKBELT wrote:
blog wrote:
If l and K are lines in xy- plane, is the product of the slope of l and k equal to -1?

1. Line l passes through the origin and the point (1,2).
2. Line K has x-intercept 4 and y-intercept 2.



C


1: we dont know anything about the other line but we can find the slope of line l = 2

2: again we dont know the other line's slope but k's is -1/2

Together 2*-1/2= -1

But you could just realize that 1 and 2 are suff together b/c we know the slopes we are going to get a YES OR A NO NOT BOTH. so u could save some time.


how come u get k's = -1/2 in 2 ?


(4,0) and (0,2) --> (0-2)/(4-0) --> -2/4 --> -1/2

Formula for slope is (y1-y2)/(x1-x2)
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Re: DS - if l and k [#permalink] New post 02 Feb 2008, 13:41
>> Line K has x-intercept 4 and y-intercept 2.

Its not clear if the x-intercept is going to be a (4,0). All it said is that x-intercept is 4 and y-intercept is 2. Even a coordinate of (-4,0) equals an x-intercept of 4.



So the x coordinates can be (4,0) or (-4,0) and y coordinates can be (0,2) or (0,-2)

So there are two possible lines that are perpendicular and the other 2 are not.

So in my opinion E.

What is the OA ?
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Re: DS - if l and k [#permalink] New post 02 Feb 2008, 16:44
my mistake if 1) is true then 2) will have a specific set of coordinates.

C is correct... :wall

Need to be more cautious.
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Re: DS - if l and k [#permalink] New post 02 Feb 2008, 20:51
neelesh wrote:
my mistake if 1) is true then 2) will have a specific set of coordinates.

C is correct... :wall

Need to be more cautious.



what do u mean by 2 has to have a specific set of cordinates .. form what i see i agree to your earlier assumption ...when u say line k has 4 as x cordinate and 2 as y cordinate u can very well say that it is a cordinate of the same point (4,2) then u cannot say anything about K's slope as it just passes through one point .. please explain as i still feel it should be E
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Re: If l and K are lines in xy- plane, is the product of the [#permalink] New post 15 Jul 2012, 22:10
Can anyone give a better explanation on this one please

Hovv does K have a slope of -1/2 out of novvhere at all

Please any expert
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Re: If l and K are lines in xy- plane, is the product of the [#permalink] New post 16 Jul 2012, 04:42
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We don't need to calculate anything to answer this question.

If L and K are lines in xy- plane, is the product of the slope of l and k equal to -1?

The product of two lines equal to -1 if these lines are perpendicular to each other. So, the question basically asks whether L and K are perpendicular to each other.

Now, if we knew the equations of each line we would be able to answer the question. What do we need to find equation of a line? Since a line is defined by two points, then if we knew any two points of a line then we could get its equatiom

(1) Line L passes through the origin and the point (1,2). We have two points of line L: (0, 0) and (1, 2). So, we can get the equation of line L, though we know nothing about line K. Not sufficient.

(2) Line K has x-intercept 4 and y-intercept 2. We have two points of line K: (4, 0) and (0, 2). So, we can get the equation of line K, though we know nothing about line L. Not sufficient.

(1)+(2) We know both equation, hence we can answer whether the lines are perpendicular to each other. Sufficient.

Answer: C.

venmic wrote:
Can anyone give a better explanation on this one please

Hovv does K have a slope of -1/2 out of novvhere at all

Please any expert


Given two points \((x_1,y_1)\) and \((x_2,y_2)\) on a line, the slope \(m\) of the line is:

\(m=\frac{y_2-y_1}{x_2-x_1}\).

Since x-intercept of line K is 4, then it passes through point (4, 0) and since y-intercept of line K is 2, the it passes through point (0, 2). Hence it's slope is \(m=\frac{2-0}{0-4}=-\frac{1}{2}\).

For more on Coordinate Geometry check: math-coordinate-geometry-87652.html

Hope it helps.
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Re: If L and K are lines in xy- plane, is the product of the [#permalink] New post 20 Oct 2012, 13:46
read 2) carefully - line K has an x-intercept of 4 (meaning it hits the x axis at 4--- so the point would therefore be 4,0) and y-intercept of 2 (meaning it hits the y axis at 2---so the point would therefore be 0,2). So we now have (4,0) and (0,2) as our two points for line K and we can plug it into our slope formula of y2 - y1/x2 - x1 --> y2 = 2 y1 = 0 x2 - 0 y1 = 4 --> 2-0/0-4 ---> 2/-4 = -1/2.


Hope this helps!
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Re: If L and K are lines in xy- plane, is the product of the [#permalink] New post 27 Jul 2015, 12:37
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Re: If L and K are lines in xy- plane, is the product of the   [#permalink] 27 Jul 2015, 12:37
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