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If m > 0 and n > 0, is (m+x)/(n+x) > m/n 1) m <

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If m > 0 and n > 0, is (m+x)/(n+x) > m/n 1) m < [#permalink] New post 22 Jun 2008, 13:33
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If m > 0 and n > 0, is (m+x)/(n+x) > m/n

1) m < n
2) x > 0
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Re: DS - GMATPrep M N [#permalink] New post 22 Jun 2008, 16:10
id say C

stat 1 is insuff because you dont know what x is

stat 2 is insuff because you dont know if m is greater than or less than n

together, you know that all values are positive, and that the LS will always be greater than the RS
Manager
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Re: DS - GMATPrep M N [#permalink] New post 22 Jun 2008, 16:18
pmenon wrote:
id say C

stat 1 is insuff because you dont know what x is

stat 2 is insuff because you dont know if m is greater than or less than n

together, you know that all values are positive, and that the LS will always be greater than the RS


You're correct, OA is C
What I thought is that since we're multiplying both sides by x then the sign won't change, I guess we need to know the sign (-ve or +ve) for x.

Thanks!
Re: DS - GMATPrep M N   [#permalink] 22 Jun 2008, 16:18
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If m > 0 and n > 0, is (m+x)/(n+x) > m/n 1) m <

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