Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

(1) m < n. No info about x. Not sufficient. (2) x >0. No info about m and n. Not sufficient.

(1)+(2) As from the above two statements nominators and denominator of both fractions are positive, we can crossmultiply --> is \(\frac{m+x}{n+x}>\frac{m}{n}\) --> is \((m+x)n>(n+x)m\) --> is \(mn+xn>mn+xm\) --> is \(x(n-m)>0\) --> as \(x>0\) and \(n>m\), then \(x(n-m)>0\) is true. Sufficient.

(1) m < n. No info about x. Not sufficient. (2) x >0. No info about m and n. Not sufficient.

(1)+(2) As from the above two statements nominators and denominator of both fractions are positive, we can crossmultiply --> is \(\frac{m+x}{n+x}>\frac{m}{n}\) --> is \((m+x)n>(n+x)m\) --> is \(mn+xn>mn+xm\) --> is \(x(n-m)>0\) --> as \(x>0\) and \(n>m\), then \(x(n-m)>0\) is true. Sufficient.

Answer: C.

Did you score 60 in the Quant or are you working with the GMAC!!!

Re: If m > 0 and n > 0, is (m+x)/(n+x) > m/n? [#permalink]

Show Tags

02 May 2014, 19:24

Hi Bunuel,

Why isn't the answer B given that in the below steps, (2) gives us the same information as in (1)?

(2) Because we know that both m and n are positive and that x is positive, we can safely cross-multiply. (m+x)*n > (n+x)*m mn + xn > mn + xm xn > xm n > m Because we now know that n > m, we can use the same steps that you used for C to answer the question and only (2) will be sufficient to answer the problem. Please tell me where I am going wrong here.

Why isn't the answer B given that in the below steps, (2) gives us the same information as in (1)?

(2) Because we know that both m and n are positive and that x is positive, we can safely cross-multiply. (m+x)*n > (n+x)*m mn + xn > mn + xm xn > xm n > m Because we now know that n > m, we can use the same steps that you used for C to answer the question and only (2) will be sufficient to answer the problem. Please tell me where I am going wrong here.

For (2) we don't know whether n>m.

The question asks whether (m+x)/(n+x) > m/n. For (2) when you simplify the question becomes is n>m? This is not given, that;s exactly what we need to find out.

Check out this awesome article about Anderson on Poets Quants, http://poetsandquants.com/2015/01/02/uclas-anderson-school-morphs-into-a-friendly-tech-hub/ . Anderson is a great place! Sorry for the lack of updates recently. I...

As you leave central, bustling Tokyo and head Southwest the scenery gradually changes from urban to farmland. You go through a tunnel and on the other side all semblance...

Ghibli studio’s Princess Mononoke was my first exposure to Japan. I saw it at a sleepover with a neighborhood friend after playing some video games and I was...