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(1) m < n. No info about x. Not sufficient. (2) x >0. No info about m and n. Not sufficient.

(1)+(2) As from the above two statements nominators and denominator of both fractions are positive, we can crossmultiply --> is \frac{m+x}{n+x}>\frac{m}{n} --> is (m+x)n>(n+x)m --> is mn+xn>mn+xm --> is x(n-m)>0 --> as x>0 and n>m, then x(n-m)>0 is true. Sufficient.

(1) m < n. No info about x. Not sufficient. (2) x >0. No info about m and n. Not sufficient.

(1)+(2) As from the above two statements nominators and denominator of both fractions are positive, we can crossmultiply --> is \frac{m+x}{n+x}>\frac{m}{n} --> is (m+x)n>(n+x)m --> is mn+xn>mn+xm --> is x(n-m)>0 --> as x>0 and n>m, then x(n-m)>0 is true. Sufficient.

Answer: C.

Did you score 60 in the Quant or are you working with the GMAC!!!

Re: If m > 0 and n > 0, is (m+x)/(n+x) > m/n? [#permalink]
02 May 2014, 18:24

Hi Bunuel,

Why isn't the answer B given that in the below steps, (2) gives us the same information as in (1)?

(2) Because we know that both m and n are positive and that x is positive, we can safely cross-multiply. (m+x)*n > (n+x)*m mn + xn > mn + xm xn > xm n > m Because we now know that n > m, we can use the same steps that you used for C to answer the question and only (2) will be sufficient to answer the problem. Please tell me where I am going wrong here.

Re: If m > 0 and n > 0, is (m+x)/(n+x) > m/n? [#permalink]
03 May 2014, 03:50

Expert's post

TooLong150 wrote:

Hi Bunuel,

Why isn't the answer B given that in the below steps, (2) gives us the same information as in (1)?

(2) Because we know that both m and n are positive and that x is positive, we can safely cross-multiply. (m+x)*n > (n+x)*m mn + xn > mn + xm xn > xm n > m Because we now know that n > m, we can use the same steps that you used for C to answer the question and only (2) will be sufficient to answer the problem. Please tell me where I am going wrong here.

For (2) we don't know whether n>m.

The question asks whether (m+x)/(n+x) > m/n. For (2) when you simplify the question becomes is n>m? This is not given, that;s exactly what we need to find out.