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If m^(-1) = -1/3 then m^(-2) is equal to

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If m^(-1) = -1/3 then m^(-2) is equal to [#permalink] New post   20 Dec 2012, 07:23
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If \(m^{(-1)} = -\frac{1}{3}\) then \(m^{(-2)}\) is equal to

(A) -9
(B) -3
(C) -1/9
(D) 1/9
(E) 9
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D
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Bunuel
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If m^(-1) = -1/3 then m^(-2) is equal to [#permalink] New post   20 Dec 2012, 07:25
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Walkabout wrote:
If m^(-1) = -1/3 then m^(-2) is equal to

(A) -9
(B) -3
(C) -1/9
(D) 1/9
(E) 9


\(m^{-1} = -\frac{1}{3}\);

\(\frac{1}{m}=-\frac{1}{3}\);

\(m=-3\).

\(m^{-2}=\frac{1}{m^2}=\frac{1}{9}\).

Answer: D.
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Re: If m^(-1) = -1/3 then m^(-2) is equal to [#permalink] New post   27 Feb 2014, 20:20
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Walkabout wrote:
If m^(-1) = -1/3 then m^(-2) is equal to

(A) -9
(B) -3
(C) -1/9
(D) 1/9
(E) 9



\(\frac{1}{m} = \frac{-1}{3}\)

Squaring both sides

\(\frac{1}{m^2} = \frac{1}{9} =\)Answer = D
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If m^(-1) = -1/3 then m^(-2) is equal to [#permalink] New post   Updated on: 12 Nov 2019, 18:21
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Walkabout wrote:
If mˉ¹ = -1/3 then mˉ² is equal to

(A) -9
(B) -3
(C) -1/9
(D) 1/9
(E) 9


Some good solutions here.
Here's one more approach:

CONCEPT: b^(-n) = 1/(b^n)

Given: mˉ¹ = -1/3
Rewrite as: 1/m = 1/(-3)
We can see that m = -3

So, mˉ² = 1/(m²) = 1/(-3)² = 1/9

Answer:
Show Spoiler
D

Originally posted by BrentGMATPrepNow on 27 Jul 2016, 07:53.
Last edited by BrentGMATPrepNow on 12 Nov 2019, 18:21, edited 1 time in total.
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Re: If m^(-1) = -1/3 then m^(-2) is equal to [#permalink] New post   28 Jun 2016, 05:48
Expert Reply
Walkabout wrote:
If m^(-1) = -1/3 then m^(-2) is equal to

(A) -9
(B) -3
(C) -1/9
(D) 1/9
(E) 9


Since we know that m^-1 = -1/3 and m^-2 = (m^-1)^2, then m^-2 = (-1/3)^2 = 1/9.

The answer is D.
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Re: If m^(-1) = -1/3 then m^(-2) is equal to [#permalink] New post   29 Jul 2016, 11:52
M^-1=-1/3=> M=-3
hence M^-2=1/9
Smash D
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Re: If m^(-1) = -1/3 then m^(-2) is equal to [#permalink] New post   29 Jul 2016, 12:14
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m^(-1) = -(1/3)
Squaring both sides
m^(-2) = 1/9

Ans. D
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Re: If m^(-1) = -1/3 then m^(-2) is equal to [#permalink] New post   27 Sep 2016, 14:26
\(m^-1 = \frac{-1}{3}\)

\(\frac{1}{m} = \frac{-1}{3}\)

By cross multiplication

\(-m = 3\)

Squaring both sides

\(m^2 = 9\)

So \(m^-2 = \frac{1}{9}\)
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Re: If m^(-1) = -1/3 then m^(-2) is equal to [#permalink] New post   19 Apr 2020, 08:12
m^(−1)=−1/3
now,squaring both sides
[m^(−1)]^2=[−1/3]^2
m^(−2)=1/9.

correct answer D
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Re: If m^(-1) = -1/3 then m^(-2) is equal to [#permalink] New post   20 Apr 2020, 08:11
Walkabout wrote:
If \(m^{(-1)} = -\frac{1}{3}\) then \(m^{(-2)}\) is equal to

(A) -9
(B) -3
(C) -1/9
(D) 1/9
(E) 9


Pretty simple and straight forward, doesn't really require any calculations.
Base raised to negative exponent = \(\frac{1}{m} = -\frac{1}{3}\) Thus \(\frac{1}{m^2} = (-\frac{1}{3})^2 = \frac{1}{9}\)
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Re: If m^(-1) = -1/3 then m^(-2) is equal to [#permalink] New post   20 Mar 2021, 20:51
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Video solution from Quant Reasoning:
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