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# If m and n are integers, is m odd? (1) n+m is odd. (2) n+m =

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Director
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If m and n are integers, is m odd? (1) n+m is odd. (2) n+m = [#permalink]  28 Oct 2006, 14:30
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If m and n are integers, is m odd?

(1) n+m is odd.

(2) n+m = n^2 + 5.

(OA may be a little late. Sorry!)
Senior Manager
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Re: DS: Is m odd? [#permalink]  28 Oct 2006, 17:46
anandsebastin wrote:
If m and n are integers, is m odd?

(1) n+m is odd.

(2) n+m = n^2 + 5.

(OA may be a little late. Sorry!)

B. 2) if n is odd (O) then right side of 2) equation will be even (E)

so O + m = E, so m must be O

if n is even then right side of equation will be O

so E + m = O, so m must be odd
Senior Manager
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B

1) Not SUFF

2)
n+m = n^2 + 5
=> n^2 â€“n + 5= m
=> n (n -1) + 5 = m
Here n (n -1) ..2 consecutive integers ..product has to even

=> even + 5 = m = odd
VP
Joined: 28 Mar 2006
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anindyat wrote:
B

1) Not SUFF

2)
n+m = n^2 + 5
=> n^2 â€“n + 5= m
=> n (n -1) + 5 = m
Here n (n -1) ..2 consecutive integers ..product has to even

=> even + 5 = m = odd

Absolutely......

It should be B and the same explanation as above
Director
Joined: 23 Jun 2005
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Kudos [?]: 15 [0], given: 1

You guys all got it right.

OA is B
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